Pls help asap!!!!!!!!

Mathematics

1 answer:

iren [92.7K]3 years ago

7 0

Answer:

13.416.

I wanted to help, and I hope this works for you. Sorry, if its incorrect.

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On a baseball

vampirchik [111]

Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.

<h3>How far did the outfielder throw the ball?</h3>

Based on the shape of a mound, the law of cosines can be used.

The distance the ball was thrown by the outfielder can therefore be d.

Distance is:

d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))

d ²= 33,484.42ft

Then find the square root:

d = √33,484.42

= 182.9874

= 183 ft

Find out more solving for distance at brainly.com/question/10739348

#SPJ1

4 0

2 years ago

GEOMETRY PROOFS!

yarga [219]

From the given figure ,

RECA is a quadrilateral

RC divides it into two parts

From the triangles , ∆REC and ∆RAC

RE = RA (Given)

angle CRE = angle CRA (Given)

RC = RC (Common side)

Therefore, ∆REC is Congruent to ∆RAC

∆REC =~ ∆RAC by SAS Property

⇛CE = CA (Congruent parts in a congruent triangles)

Hence , Proved

Additional comment:-

SAS property:-

"The two sides and included angle of one triangle are equal to the two sides and included angle then the two triangles are Congruent and this property is called SAS Property (Side -Angle-Side)

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