Answer:
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
||Vel_jet_r|| = 465.993 mph
Step-by-step explanation:
We need to decompose the velocity of the wind into a component that can be added (or subtracted from the velocity of the jet)
The velocity of the jet
500 mph North
Velocity of the wind
50 mph SouthEast = 50 cos(45) East + 50 sin (45) South
South = - North
Vel_ wind = 50 cos(45) mph East - 50 sin (45) mph North
Vel _wind = 35.35 mph East - 35.35 mph North
This means that the resulting velocity of the jet is equal to
Vel_jet_r = (500 mph - 35.35 mph) North + 35.35 mph East
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
An the jet has a magnitude velocity of
||Vel_jet_r|| = sqrt ((464.645 mph)^2 + (35.35 mph)^2)
||Vel_jet_r|| = 465.993 mph
Answer:
10
Step-by-step explanation:
QT=ST/2=√(12^2+16^2)/2=10
Answer: 16517 dollars
Step-by-step explanation:
Given that x is the number of years after 2000.
In 2005, the number of years x = 4
Because the equation was modelled for 4 year college courses
The best estimate for the average cost of tuition in 2005 will be
ŷ = 937.98(4) + 12,764.90
Y = 3751.92 + 12764.9
Y = 16516.82 dollars
Y = 16517 dollars
The answer to your question is 8, because you replace z with 2
I did the first one.
a. The equation that you need to get DF.
b. Substitute the values in the equation.
c. Add up the rs and the numbers (to simplify).
d. divide both sides by 5 to get r.
e. The value of r is given.
