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igor_vitrenko [27]
3 years ago
10

en el octagono regular siguiente cuyo lado mide 2 cm. se han trazado arcos de circunferencia de radio 1 en cada uno de los ángul

os interiores. el área sombreada de la misma que en la contenida en los tres círculos cada uno de ellos de radio 1 cm​

Mathematics
1 answer:
AnnZ [28]3 years ago
6 0

Answer:

the answer is easy.

Step-by-step explanation:

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The distance from the Earth to the Sun is approximately 90,000,000 miles, which can be written as 9 × 10a miles, where a = . The
andrey2020 [161]

10*a = 10000000

a = 1000000, one million

5*10*b = 500000000

b = 10000000, ten million

About ten times.

7 0
3 years ago
Read 2 more answers
Solve the system of linear equations by substitution.
Anastasy [175]

Answer: The solution is the ordered pair (1/2,  -3/4) so x = 1/2 and y = -3/4 pair up together. The two lines, when graphed, cross at this location.

note: 1/2 = 0.5 and -3/4 = -0.75; so the intersection point can be written as (0.5, -0.75)

===================================================

Explanation:

The second equation has y isolated. We can replace the y in the first equation with the expression 1/2x - 1

3x + 2y = 0

3x + 2( y ) = 0

3x + 2( 1/2x - 1) = 0 ... y is replaced with 1/2x-1

3x + 2(1/2x) + 2(-1) = 0 .... distribute

3x + x - 2 = 0 .... note how 2 times 1/2 is 1

4x - 2 = 0

4x = 2

x = 2/4

x = 1/2

Use this x value to find the y value it pairs with

y = (1/2)*x - 1

y = (1/2)*(1/2) - 1 ... replace x with 1/2

y = 1/4 - 1

y = 1/4 - 4/4

y = (1-4)/4

y = -3/4

8 0
3 years ago
You use pemdas and they both equal to 77. So yes they are equivalent.
spayn [35]

Answer:

yes if u use Pemdas and both sides of the equation have the same answer, they both are equivalent.

Good job!

7 0
3 years ago
You have two fair, six-sides dice. However, the dice have been modified so that instead or 1,2,3,4,5,6 the sides are numbered 1,
Tamiku [17]

Answer:

30.56%

Step-by-step explanation:

Let the sides on each dice be labeled as 1, 2a, 2b, 2c, 3, 4.

The sample space for the sum of the values being 4 is:

S={1,3; 3,1; 2a,2a; 2a,2b; 2a,2c; 2b,2a; 2b,2b; 2b,2c; 2c,2a; 2c,2b; 2c,2c}

There are 11 possible sums out of the 36 possible outcomes that result in a sum of 4. Therefore, the probability their total is 4 is:

P(S) =\frac{11}{36}=0.3056 =30.56\%

There is a 30.56% probability that their sum is 4.

6 0
3 years ago
Evaluate the following expression.<br><br> (-3)-2
pentagon [3]
-5 here the answer is really good give me more like that
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