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BigorU [14]
3 years ago
6

3 A circle centered at the origin has a radius

Mathematics
1 answer:
tankabanditka [31]3 years ago
8 0

Step-by-step explanation:

x = 7 cos 210 = 7×(-½√3) = -3.5√3

y = 7 sin 210 = 7×(-½) = -3.5

point C (-3.5√3 , -3.5)

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13.6z - 11 = -1.48. <br> can u please show the work for it
serious [3.7K]

Step-by-step explanation:

13.6z - 11 = -1.48.

13.6z=-1.48+11

z=9.52/13.6=0.7

7 0
3 years ago
O is the centre of the circle and ABC and EDC are rangers to the circle. Find the side of angle BCD. You must give reason in you
AleksandrR [38]

Every line from the tangent to the centre is 90°. This is said in the circle theorems.

So angle OBC and ODC are 90°.

angle O is twice the size of angle F. This is another circle theorem.

Therefore angle O is 152°.

The quadrilateral of ODBC would equal to 360°. Which means 90° + 90° + 152° = 332°

360° - 332° = 28°.

The answer is 28°

4 0
3 years ago
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Someone pls help I will mark brainliest
vekshin1
C is the answer!! I hope this helps!!!
4 0
3 years ago
Subject to some of (3/5 + 1/5i) and (4/5 - 2/5i) from (9/5 - 1/5i). the result is what
romanna [79]

The correct answer is: 2/5.

Explanation:

First you have to add the following expressions:

(\frac{3}{5}+\frac{1}{5}i)+(\frac{4}{5}-\frac{2}{5}i) \\ (\frac{3}{5}+ \frac{4}{5})+(\frac{1}{5}i-\frac{2}{5}i) \\= \frac{7}{5}-\frac{1}{5}i

Now subtract the above expression from (\frac{9}{5}-\frac{1}{5}i):

(\frac{9}{5}- \frac{1}{5}i) - (\frac{7}{5} -\frac{1}{5}i) \\ (\frac{9}{5} -\frac{7}{5}) + (\frac{1}{5}i -\frac{1}{5}i) \\ \frac{2}{5} \\


Hence the correct answer is 2/5.


7 0
3 years ago
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A triangle has side lengths of 13 cm and 6 cm. Which could be the value of the third side, 21 cm or 17 cm?
Yuri [45]

Answer:

No

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4 0
3 years ago
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