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bixtya [17]
3 years ago
5

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Mathematics
2 answers:
ozzi3 years ago
5 0
AaaaaAaaaAaAAAaaaaaaaaaaaaaaaaaAaaaAaaaaaaAaaaAaa
irakobra [83]3 years ago
4 0

☁️ Answer ☁️

Hamood?

Hamood

Hamood

Hamood habibi Hamood, Hamood habibi

Hamood habibi Hamood, Hamood habibi

Hamood?

Hamood

Goum eg'ad men ennoama!

Goum eg'ad men ennoama! Goum eg'ad men ennoama!

Ya Ahmad Hamadi

Ya Ahmad Hamadi

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What is the surface area of the solid that this net can form? (I’m hoping that picture is attached)
Roman55 [17]

Answer:

210 cm^2

Step-by-step explanation:

The left rectangle is 65 cm^2, the middle rectangle is 60 cm^2, the right rectangle is 25 cm^2, and the two triangles are each 30 cm^2

4 0
4 years ago
Name a point that is 20 units away from (5,-2)​
Fudgin [204]

Answer:

Distance between both points is 20units.

Applying the Distance between Points Formula

d= √(y₂-y₁)²+(x₂-x₁)²

x₁= 5 y₁=–2

x₂= ? y₂= ?

20 = √ [y -(-2)]² + (x - 5)²

Taking the square of both sides to eliminate the square root on the right.

20² = ( y + 2)² + (x - 5)²

400 = y² + 4y + 4 + x² – 10x + 25.

400 = x² + y² – 10x + 4y + 29.

x² + y² – 10x + 4y = 400 – 29

x² + y² – 10x + 4y = 371--------------eqn 1.

We called that eqn 1 cause we need another equation to solve this.

To solve an Equation with 2 variables... You need 2 equation.

To solve that of 3 variables.... you need 3 equations(Basic Math Rules).

We're dealing with 2 variables in this case(x, y).

Now

We'd need to think in order to create another equation that'll satisfy the distance or point.

We know that the distance between both Points(known and unknown) is 20.

Half that distance is 10.

The distance of 10 will occur at the center of these 2 points.

So lets apply the formula for Mid point to get the coordinate of the center.

Midpoint

let p be the x position and q be the y position of the midpoint

p = (x₁ + x₂)/2. q = (y₁ + y₂)/2

Starting from the know point (5 , -2)

x₁=5 y₁=–2

p = (5 + x)/2. q = (–2 + y)/2

p = (x + 5)/2 q = (y–2)/2.

This is the coordinate of the Midpoint.

Now We know that the distance between (5, -2) and [(x + 5)/2 , (y–2)/2] is 10(midpoint).

Applying the distance between points again.

d = √(y₂ - y₁)² + (x₂ - x₁)²

x₁= 5 y₁= -2

x₂= (x + 5)/2 y₂= (y–2)/2

10 = √[(y–2)/2 -(-2)]² + [ (x+5)/2 – 5)]²

10 = √[(y–2)/2 + 2]² + [(x+5)/2 – 5)]²

Squaring both sides to remove square root on the right and also Taking the LCM in each bracket

We have

10² = [ (y + 2)/2]² + [ (x–5)/2]²

Distributing the "2" on the denominator to each individual number in the parentheses.

100 = (y/2 + 1)² + (x/2 – 5/2)²

100 = y²/4 + y + 1 + x²/4 –5x/2 + 25/4.

Multiply through by 4 to clear fractions.

400 = y² + 4y + 4 + x² – 10x + 25

Rearranging

x² + y² – 10x + 4y = 371.

Hmm...

Equation 1 and 2 Are the Same.

Something is Wrong!

Pls Recheck the Question

I do believe that One value of the unknown point should be given.

I maybe be wrong somewhere else too.

Pls correct in the comment section if you spot it.

7 0
3 years ago
1. Label all vertices on trapezoid A B C D.
saul85 [17]

Answer:

Step-by-step explanation:

Rigid transformation:

Translation, reflection and rotation are the example rigid transformation, in which size and shape of a figure doesn't change after the transformation.

Image A'B'C'D' will be exactly same as original trapezoid ABCD shown in the figure attached.

∠B ≅ ∠B'

∠A ≅ ∠A'

AB = A'B' = 6 units

CD = C'D' = 4 units

7 0
3 years ago
Find the lcd of the three rational expressions​
Tom [10]
The least common denominator is C!

Hope this helps you! :)
5 0
3 years ago
Plzzzzzzzzzzzzzzzzzz help quick
Bezzdna [24]

Answer:

The correct way to set up the slope formula for the line that passes through points (5 , 0) and (6 , -6) is  \frac{-6-0}{6-5} ⇒ C

Step-by-step explanation:

The formula of the slope of a line passes through points (x_{1},y_{1}) and (x_{2},y_{2})

is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

∵ The line passes through points (5 , 0) and (6 , -6)

∴ x_{1} = 5 and  x_{2} = 6

∴  y_{1} = 0 and  y_{2} = -6

Substitute these values in the formula of the slope

∵ m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

∴ m=\frac{-6-0}{6-5}

Let us look to the answer and find the same formula

The answer is:

The correct way to set up the slope formula for the line that passes through points (5 , 0) and (6 , -6) is  \frac{-6-0}{6-5}

8 0
3 years ago
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