Answer:
Step-by-step explanation:
The distance from one score to another tends to increase, and a single score tends to provide a less accurate representation of the entire distribution.
Consider normal distribution it has increasing trend from -Inf to the mean. But has no probability at any point. But if you consider binomial distribution then you will get the information at any integer of its range, but not all values of real line. That is you will not have information on (0,1) so there you cannot comment for increment of that distribution.
Answer:
gzgkvxgujdruutdtuhfdykjzfuk
Answer:
-1/3
Step-by-step explanation:
hope this helps
<em>Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work. </em>
<em>But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.</em>
Answer:
We conclude that whoever (between Tamara and Clyda's work) may have got the answer as
after dividing
by
, would be the one who solved it correctly.
Step-by-step explanation:
Considering the expression

Lets divide the expression by 
Solution Steps:

Factorizing

Factorizing




Thus,

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as
after dividing
by
, would be the one who solved it correctly.
Keywords: expression, division
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Given:
The probability for success of an event is P(A)
The probability of success of a second, independent event is P(B).
To find:
The probability of both events occurring, in that order.
Solution:
If A and B are two independent events, then

It is given that,
The probability for success of an event is P(A)
The probability of success of a second, independent event is P(B).
Since A and B both are independent event and we need to find the probability of both events occurring, in that order, i.e.,
, therefore
.
Hence, the correct option is A.