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Lina20 [59]
3 years ago
12

To make purple plum paint, the paint store mixes blue and red paint in a ration of 8:5 if a customer needs 65 gallon of paint ho

w many gallons blue and red paint needs to go in the mix
Mathematics
1 answer:
Olegator [25]3 years ago
3 0

Answer:

Number of gallons of blue paint = 40 gallons

Number of gallons of red paint = 25 gallons

Step-by-step explanation:

We are given the ratio:

Blue paint : Red paint =

8 : 5

Sum of proportion = 8 + 5 = 13

If the customer need 65 gallons of paint,

a) Number of gallons of blue paint needed =

8/13 × 65 gallons = 40 gallons

b) Number of gallons of red paint needed =

5/13 × 65 gallons = 25 gallons

Therefore:

Number of gallons of blue paint = 40 gallons

Number of gallons of red paint = 25 gallons

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dimaraw [331]
7.

The slope will be 200 since it increases by two hundred per week

The equation for this would be

y = 200x

8.

J would be the best table
3 0
3 years ago
Add (1.3t3 + 0.4t2 – 24t) + (8 – 18t + 0.6t2) For each term in the second polynomial, enter the letter showing where that term s
nignag [31]

Answer:

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t  + 8

Step-by-step explanation:

Given

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)

Required

Solve

We have:

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)

Collect like terms

1.3t^3 + 0.6t^2 + 0.4t^2 - 24t- 18t  + 8

1.3t^3 + t^2 -42t  + 8

So:

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t  + 8

8 0
3 years ago
Need help asap pls!!!
lisabon 2012 [21]

Answer:

16

Step-by-step explanation:

According to the given description, PS is the mid segment of the \triangle TQR

Therefore by Mid-segment Theorem:

PS = \frac{1}{2}  QR \\  \\ PS = \frac{1}{2}   \times 32 \\  \\ PS =16 \:

3 0
3 years ago
Find the nonpermissible replacement for y in<br> this expression.<br> y + 9<br> y+7
BigorU [14]

Answer:

idk

Step-by-step explanation:

3 0
3 years ago
Data consistent with summary quantities in the article "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among
Olegator [25]

Answer:

a) X[bar]₁=  1839.20 cal

b) X[bar]₂= 1779.07 cal

c) S₁= 386.35 cal

Step-by-step explanation:

Hello!

You have two independent samples,

Sample 1: n₁= 15 children that did not eat fast food.

Sample 2: n₂= 15 children that ate fast food.

The study variables are:

X₁: Calorie consumption of a kid that does not eat fast food in one day.

X₂: Calorie consumprion of a kid that eats fast food in one day.

a)

The point estimate of the population mean is the sample mean

X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal

b)

X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal

c)

To calculate the sample standard deiation, you have to calculate the sample variance first:

S₁²= \frac{1}{n_1-1}[∑X₁² - (( ∑X₁)²/n₁)]= \frac{1}{14} + [52829538 - (\frac{27588^{2} }{15}) = 149263.4571 cal²

S₁= 386.35 cal

I hope it helps!

7 0
3 years ago
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