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Alex_Xolod [135]
3 years ago
7

Match the equation with the proptery used

Mathematics
1 answer:
ycow [4]3 years ago
7 0

Answer:

what equation   ?

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Started business whit cash Rs 250000 and Machinery Rs 200000<br>Accounting equation ​
oksano4ka [1.4K]

\huge\purple{Answer}

In case there is no double entry system is followed, profit can be calculated by comparing the opening and closing capital. In the given situation this can be calculated as:

Opening Capital Rs.200000

Add: Capital Introduced Rs.200000

Add: Profit for the year Rs. 250000

Less: Loss for the year Rs.NIL

Less: Drawings Rs. 30000

--------------------

Capital at the end of the year Rs.620000

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Loan taken is a liability and loan given is asset, that will not affect the capital.

<h2>ƑƠԼԼƠƜ MЄ❤</h2>
7 0
3 years ago
Read 2 more answers
Which table does NOT represent a linear function?
chubhunter [2.5K]

Hey there!
Linear functions have a continuous change.

Let's check these tables and see if we can tell linear functions from non-linear functions.

The first one is

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 8, 5, 2, -1

- we subtract 3 each time

\rule{200}{2}

Let's try the next one:

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 5, 10, 15, 20

- we add 5 each time

\rule{200}{2}

Let's try the third one:

  • x values: -1, 0, 1, 2
  • - we add 1 each time
  • y values: 15, 18, 20, 21

        - we add 3, then 2, then 1..

So this table doesn't represent a linear function.

Let's check the fourth one:

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 1, 2, 3, 4

- we add 1 each time

Thus, Option C is the right option.

Hope everything is clear.

Let me know if you have any questions!

Always remember: Knowledge is power!

4 0
2 years ago
Gianna used 11.9 yards of fabric to make 7 same-sized aprons for the cooking club. How much fabric did Gianna use per apron?
docker41 [41]

Answer:

Step-by-step explanation:

11.9 divided by 7 = 1.7

She uses 1.7 yards per apron

5 0
3 years ago
Can someone help me figure out the answer?
Ahat [919]

Answer:

You will break even on the car wash when you buy 13.5 gallons. As long as you buy that or more, it is cheaper to get the car wash.

Step-by-step explanation:

In order to find this, we need to create equations for both situations. If we let x equal the amount of gallons purchased, we can model the first equation as:

f(x) = 3.35x

And the second equation as:

f(x) = 3.05x + 4.05

Then to find when they equal each other, we can set the two equations equal to each other and solve for x.

3.35x = 3.05x + 4.05

0.30x = 4.05

x = 13.5

This means once you buy 13.5 gallons, the prices will be the same. Any amount over that and the car wash will be cheaper

6 0
3 years ago
On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)
xz_007 [3.2K]

Answer:

P = 10 + 2\sqrt{53} units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3),  X (2, 3),

Y (4, -4),  Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

For WX:

(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)

WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}

WX = \sqrt{(-5)^2 + (0)^2}

WX = \sqrt{25}

WX = 5

For XY:

(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)

XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}

XY = \sqrt{-2^2 + (3 +4)^2}

XY = \sqrt{-2^2 + 7^2}

XY = \sqrt{4 + 49}

XY = \sqrt{53}

For YZ:

(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)

YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}

YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}

YZ = \sqrt{7^2 + (-2)^2}

YZ = \sqrt{49 + 4}

YZ = \sqrt{53}

For ZW:

(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)

ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}

ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}

ZW = \sqrt{0^2 + (-5)^2}

ZW = \sqrt{0 + 25}

ZW = \sqrt{25}

ZW = 5

The Perimeter (P) is as follows:

P = WX + XY + YZ + ZW

P = 5 + \sqrt{53} + \sqrt{53} + 5

P = 5 + 5 + \sqrt{53} + \sqrt{53}

P = 10 + 2\sqrt{53} units

6 0
4 years ago
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