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Andreas93 [3]
3 years ago
5

The output y and input x of a device are related by y = x + 1.4x3 . (a) Find the values of the output for steady-state operation

at the two operating points xo = 1 and xo = 2. (b) Obtain a linearized model for both operating points and compare them.
Mathematics
1 answer:
erma4kov [3.2K]3 years ago
5 0

Answer:

a) y(1) = 2.4 , y(2) = 13.2, b) y(x) = 2.4 + 5.2\cdot (x-1), y(1) = 2.4, y(2) = 7.6

Step-by-step explanation:

a) The values of the output for steady-state operation are:

y(1) = 1 + 1.4\cdot (1)^{3}

y(1) = 2.4

y(2) = 2 + 1.4\cdot (2)^{3}

y(2) = 13.2

b) The formula for linearization is:

y(x) = y(1) +\frac{dy}{dx}|_{x = 1} \cdot (x-1)

The first derivative of the formula evaluated at x = 1 is:

\frac{dy}{dx}|_{x=1} = 1 + 4.2\cdot (1)^{2}

\frac{dy}{dx}|_{x=1} = 5.2

The linearized model is:

y(x) = 2.4 + 5.2\cdot (x-1)

The output at x = 2 is presented below:

y(2) = 2.4 + 5.2\cdot (2-1)

y(2) = 7.6

Linearized model offers reasonable approximations for small intervals.

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Solve 2/3 - 6y = - 1 5/6
alukav5142 [94]

Answer:

<u> y = 19/36</u>

Step-by-step explanation:

Assuming that what you want is the value of y, you can pass all the right side stuff to the left, and the y to the right:

2/3 + 15/6 = 6y

Then you can sum the fractions on the left by using the same denominators:

4/6 + 15/6 = 6y       ==>      19/6 = 6 * y

then  you can pass the 6 that is multiplying on the right to the left - now dividing:

<u> y = 19/36</u>

3 0
2 years ago
Read 2 more answers
Celik, S. (2011). A media comparison study on first aid instruction. Health Education Journal. 72(1), 95-101
aniked [119]

Answer:

The answer is "Option a".

Step-by-step explanation:

In the given scenario, The appropriate test for the teaching profession's accomplishment pre and post-class would be the two-sample t-test with dependent samples, that's why choice "a" is correct.

7 0
3 years ago
......ssssssssssssssssssssssssssssssssssssshhhhhh
Darina [25.2K]

Hey there! I'm happy to help!

Step 2 is incorrect. She added 4 and 2 first, but you are supposed to multiply and divide first. Then she multiplied 6 and 6, which is 36. Then she divided 36 and 2, which is 18, and then she subtracted 7, giving her 11. Step 2 is what threw the whole thing off.

Here is what Sandy should have done.

STEP 1: 6·4+2÷2-7

STEP 2: 24+1-7

STEP 3: 25-7

STEP 4: 18

I hope that this helps! Have a wonderful day! :D

3 0
3 years ago
Read 2 more answers
Help quick or else trouble
sasho [114]

Answer:

1/21

Step-by-step explanation:

2/7 ÷ 6 =

2/7 x 1/6 = 2/42

Simplify by dividing the numerator and denominator by 2

1/21

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

7 0
3 years ago
A test consists of 10 true or false questions. To pass the test a student must answer at least eight questions correctly. If the
forsale [732]
<h3>The probability of  student passing the quiz with  at least 50% of the questions correct is 0.05457.</h3>

Step-by-step explanation:

Here, the total number of T/F question = 10

The minimum answers needed correctly answered = 8

So, student needs to answer at least 8 questions correctly.

Here, the possibility of answering a question correctly  = (\frac{1}{2})   = p = 0.5

Also, the possibility of answering a question wrong  = (\frac{1}{2})  = q = 0.5

Now, to pass he needs to answer 8 or more (  8 , 9 or 10) answers correctly.

P(answering 8 correct answer)  = ^{10}C_8(p)^8(q)^2 = ^{10}C_8(0.5)^8(0.5)^2  = 0.0439

P(answering 9 correct answer)  =  ^{10}C_9(p)^9(q)^1 = ^{10}C_9(0.5)^9(0.5)^1  = 0.0097

P(answering 10 correct answer)  = ^{10}C_{10}(p)^{10}(q)^0 = ^{10}C_{10}(0.5)^{10}(0.5)^0  = 0.00097

So, the total Probability   = P(8) + P(9) + P(10)

= (0.0439) + (0.0097) + (0.00097)

= 0.05457

Hence, the probability that the student passes the quiz  with  at least 8 of the questions correct is 0.05457.

6 0
4 years ago
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