First, we need to think about what we're actually solving for: the area of the path. To find this, we can find the area of the whole thing, minus the area of the pool.
The diagram would look something like the picture I attached. We know that to find the area of a circle, you do πr^2. The radius is half of the diameter, so halve the diameters:
22/2 = 11 yards
32/2 = 16 yards
Then solve for the area of both circles.
π
![11^{2}](https://tex.z-dn.net/?f=%2011%5E%7B2%7D%20)
![= 121](https://tex.z-dn.net/?f=%3D%20121)
π ≈ <span>380.13 (area of the pool)</span>
π
![16^{2}](https://tex.z-dn.net/?f=%2016%5E%7B2%7D%20)
![= 256](https://tex.z-dn.net/?f=%3D%20256)
π ≈ <span>804.25 (area of the whole thing)
</span>
Next, subtract the area of the pool from the area of the whole thing to find the area of the walkway:
![804.25 - 380.13 = 424.12](https://tex.z-dn.net/?f=804.25%20-%20380.13%20%3D%20424.12)
(area of the walkway)
Finally, divide the area of the walkway by 6 to see how many gallons of paint you'll need:
424.12 ÷ 6 ≈ 70.69
So you'll need 71 gallons of paint!
Hope I helped and let me know if you have any questions :)
-4x + 2y = -6
2y = 4x - 6
y = 2x - 3....y int = -3 , x int = (3/2,0)
I believe it is going to be : -4x + 2y = -6
The surface area of the cube is 1536 square feet because (16×16)×6=1536 square feet. Hope it help!
Answer:
Step-by-step explanation:
To do this, we must use the unit circle. At the angle
the coordinate pair is (
,
) and the hypotenuse is 1
Now that we know these we can start using the trig functions
sin = y
cos = x
tan = ![\frac{y}{x}](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7Bx%7D)
And the other functions would be the reciprocal of these
csc = ![\frac{1}{y}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7By%7D)
sec = ![\frac{1}{x}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%7D)
cot = ![\frac{x}{y}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D)
This would mean that
sinx = ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
cosx =![\frac{\sqrt{3} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B2%7D)
tanx =
or
if you're supposed to rationalize your denominators
cscx = 2
secx =
or ![\frac{2\sqrt{3} }{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Csqrt%7B3%7D%20%7D%7B3%7D)
cot = ![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
Answer:
x=4
Step-by-step explanation:
Because we know that PQ = RS, we can use the transitive property to replace PQ in the first equation with 29:
9x-7=29
1) Add 7 to both sides:
9x=36
2) divide by 9 on both sides:
x=4