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andre [41]
3 years ago
7

When a system of linear equations is graphed, how is the graph of each equation related to the solutions of that equation?​

Mathematics
1 answer:
Kay [80]3 years ago
7 0

Answer:

The solution of such a system is the ordered pair that is a solution to both equations. To solve a system of linear equations graphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect.

Step-by-step explanation:

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A business has two loans totaling $50,000. One loan has a rate of 8% and the other has a rate of 12%. This year, the business ex
Debora [2.8K]

Answer:

the 8% loan has a principal of $37500

the 12% loan has a principal of $12500

Step-by-step explanation:

Let's start by writing the general  equation for the interest hwre I is the interest, P is the principal (in our case would be loan amounts), "r" is the interest rate in decimal form (in our case one would be 0.12, and the other one 0.08), and t is the time in years (in our case 1 year).

I=P*r*t

Then we write the interest equation coming from each loan at the end of this year (we call I1 the interest coming from the 12% loan and I2 the interest coming from the 8% one). Since we don't know the loan amounts (in fact those are what we need to find) we will name one "x" and the other "y":

I=P*r*t\\I1=x * 0.12*1\\I2=y*0.08*1

Next, we add these last two equations term by term, and replace the addition of both interests by $4500 as given in the information:

I1=x * 0.12*1\\I2=y*0.08*1\\I1+I2 = 0.12x+0.08y\\4500=0.12x+0.08y

This is our first equation in the variables x and y which are our unknowns.

Now we generate the second equation on x and y by writing in agebraic terms the other piece of information we have: "the total of the two loans is $50000. That is the addition of the principals x and y should equal $50000:

x+y=50000

We solve for y in this last equation and replace its form in terms of x in the equation of the interest, and solve for the unknown x:

y=50000-x\\4500 = 0.12x +0.08 y\\4500=0.12x+0.08(50000-x)\\4500=0.12x+4000-0.08x\\4500=0.12x-0.08x+4000\\4500=0.04x+4000\\4500-4000=0.04x\\500=0.04x\\x=\frac{500}{0.04} =12500

Therefore the amount of the loan at 12% is $12500

Now to find the amount of the second loan "y" we use the equation for the totals of the loans:

x+y=50000\\12500+y=50000\\y=50000-12500=37500

Therefore, the loan at 8% is $37500

5 0
3 years ago
Find the midpoint of the segment with the given endpoint M(-2,1) and N (-3,2)
Aleks04 [339]
(-2,1)
(-2.5,1.5)
(-3,2)
3 0
3 years ago
A carpenter can make at most 20 tables and at most 30 chairs per day. Each
baherus [9]

Answer:Its B

Step-by-step explanation:

6 0
3 years ago
What is the result if you divide 18r4 s5 t6 / -3 r2 st3 ?
coldgirl [10]
The answer for the given above is letter "a, -6r2s4t3". This is obtained by dividing 18 by -3 and subtracting the exponent below with that from above of the same variable. For r, subtract 2 from 4 to get 2. For s, subtract 1 from 5 to get 4 and lastly for t, subtract 3 from 6 to get 3. 
5 0
3 years ago
Read 2 more answers
Jamie is buying 5 concert tickets, and he wants his total cost to be no more than $4 Above or below $80. Which inequality models
kumpel [21]

Answer:

Option C \left|80-5x\right|\le 4

Step-by-step explanation:

Let

x ----> the cost of the concert ticket

we know that

The total cost to be no more than $4 Above  $80

so

5x\leq 80+4

Solve for x

x\leq \$16.80

The total cost to be no more than $4  below $80

so

5x\geq 80-4

Solve for x

5x\geq 76

x\geq \$15.2

therefore

The inequality that represent this problem is

\left|5x-80\right|\le 4

<u><em>Verify</em></u>

<em>First solution (positive case</em>)

+(5x-80)\le 4

5x\le 80+4

Solve for x

x\leq \$16.80 ----> is ok

<em>Second solution (negative case)</em>

-(5x-80)\le 4

Multiply by -1 both sides

(5x-80)\ge -4

5x\geq 80-4

Solve for x

5x\geq 76

x\geq \$15.2 ---> is ok

Remember that

\left|5x-80\right|\le 4 is equivalent to \left|80-5x\right|\le 4

Because is a absolute value

8 0
3 years ago
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