Its the first one, (-8,8) (2,2)
<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer:
She needs to do 23 sex a day and big pssyyyyyy
Step-by-step explanation:
uhhhhh
Answer:
if your looking for x then
Step-by-step explanation:
first add in the y by doing 10x+5(2x-3)=15 then 10x+10x-15=15 then 20x-15=15 then 20x=30 then divided by 20 for both sides which gets you x=30/20 or 1 1/3
Answer:
46 and 277
Step-by-step explanation:
Given
f(x) = 
- 8x - 11 ← substitute x = 3, x = - 4 into f(x)
f(3) = 
- 8(3) - 11 = 81 - 24 - 11 = 81 - 35 = 46
f(- 4) = 
- 8(- 4) - 11 = 256 + 32 - 11 = 288 - 11 = 277
