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Lunna [17]
3 years ago
13

What is the pair of vertical angles.

Mathematics
2 answers:
kobusy [5.1K]3 years ago
8 0

Answer:

C.

Step-by-step explanation:

Tatiana [17]3 years ago
6 0

Answer:

=answer is the vertical angles

C

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Solve the equation. Then check your solution. – two-fifths + a = One-fifth a. Three-fifths c. StartFraction 3 Over 10 EndFractio
VLD [36.1K]

Answer:

a = Negative one-fifth

Step-by-step explanation:

The given equation is :

\dfrac{2}{5}+a=\dfrac{1}{5}

We need to find the value of a.

Subtract 2/5 from both sides.

\dfrac{2}{5}+a-\dfrac{2}{5}=\dfrac{1}{5}-\dfrac{2}{5}\\\\a=\frac{1}{5}-\frac{2}{5}\\\\a=\dfrac{-1}{5}

So, the correct answer is Negative one-fifth. Hence, the correct option is (b).

5 0
3 years ago
What is the value of Negative 3 m n + 4 m minus 3 when m = 2 and n = negative 4? -43 -40 5 29
Ghella [55]

Answer:

Step-by-step explanation:

-3m*n+4m-3 when m=2:n=-2

-3(2)*(-2)+4(2)-3=

12+5=17

8 0
3 years ago
Read 2 more answers
Question 7 of 10
Ganezh [65]

Answer:

  • Option B

Step-by-step explanation:

Given Equation :

\qquad \sf \dashrightarrow \: 3(4x+3) = 2x - 5(3 - x) + 2

Using distribute property:

\qquad \sf \dashrightarrow \: 12x + 9 = 2x - 15 + 5x + 2

Adding the like terms we get :

\qquad \sf \dashrightarrow \: 12x + 9 = 2x  + 5x  - 15 + 2

\qquad \sf \dashrightarrow \: 12x + 9 = 7x  - 13

Transposing the variables on the right side and constant terms on the left side :

\qquad \sf \dashrightarrow \: 12x  - 7x =   - 13 - 9

\qquad \sf \dashrightarrow \: 5x =   - 22

Dividing both sides by 5 :

\qquad \sf \dashrightarrow \:  \dfrac{5x}{5}  =  \dfrac{ - 22}{5}

\qquad \bf \dashrightarrow \:  x =  \dfrac{ - 22}{5}

3 0
3 years ago
Which are measurements of the sides of a right triangle A)202,198,40 B)28,26,12 C)17,14,6 D)all of the above
iren2701 [21]
Off my research B hope its right
5 0
3 years ago
Factor -75c^2-45c+12
motikmotik

Answer: −3(5c+4)(5c−1)

Step-by-step explanation:

1. Find the Greatest Common Factor (GCF).

GCF=3

2. Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

3(75c^2/3+45c/3−12/3)

3. Simplify each term in parentheses.

−3(25c^2+15c−4)

4. Split the second term in 25c2+15c−4 into two terms.

−3(25c^2+20c−5c−4)

5. Factor out common terms in the first two terms, then in the last two terms.

−3(5c(5c+4)−(5c+4))

6. Factor out the common term 5c+4

−3(5c+4)(5c−1)

4 0
3 years ago
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