Eₖ = √1/2 mv²
Eₖ/v² = 1/2 m
2Eₖ/v² = m
mgh = 1/2 mv²
gh = 1/2 v²
2gh = v²
v = √2gh
= √2 × 10 N/kg × 2 m
= 6.324 ms⁻¹
m = 9.8/(6424)²
= 9.8/39.993
= 0.245 g
I am not sure if it's correct.
i transposed for m in the first equation then to find the velocity I combined the potential and kinetic energy equation. there was no mass because velocity doesn't depend on the mass
Then I used earth's gravitational field strength (g) 10 N/kg and the 2 m was the height provided in the question
you can try working and see if you get the same
It is our primary protection from strong UV-B electromagnetic radiation from the sun.
~Hello there! ^_^
Your question: The movement of winds during the day from the sea to the land is known as a _______ ________.
Your answer: The movement of winds during the day from the sea to the land is known as a sea breeze.
Hope this helps~
Answer:
The atmosphere is <u>layer </u><u>of </u><u>gases </u><u>around</u><u> </u><u>the</u><u> </u><u>earth </u><u>which </u><u>protect </u><u>earth </u><u>from </u><u>UV </u><u>rays.</u>
