All categories

3 years ago

In the figure shown, AB = 8 and AD = 5. What is BC?

Mathematics

1 answer:

Aloiza [94]3 years ago

4 0

Answer:

i want to say three

Step-by-step explanation:

You might be interested in

Find p(-4) and p(2) for the function p(x)=11x^5-11x^4-5x^2+15x-8

egoroff_w [7]

hi,

you must replace x by the number between parenthese.

I show you with the first one and let you do the second one

p(x) = 11x^5 -11x^4 - 5x^2 +15x-8

p(-4) = 11 (-4)^5 - 11 (-4)^4 -5(-4)² +15(-4) -8

p(-4) = 11 ( -1024- 256) - 5*16 -60-8

p(-4) = 11 ( -1280) -80-60-8

p(-4) = - 14080 - 148

p(-4) = - 14 228

7 0

3 years ago

For the given function f and g, complete parts (a)-(h). For parts (a)-(d), also find the domain.

kakasveta [241]

Answer:

a) (f + g)(x) = 9x + 1

Domain: x ε R

b) (f - g)(x) = (-5x + 13)

Domain: x ε R

c) (f.g)(x) = 14x² + 37x - 42

Domain: x ε R

d) (f/g)(x) = (2x + 7)/(7x -6)

Domain: (x ε R except x = 6/7)

e) (f + g)(7) = 64

f) (f - g)(2) = 3

g) (f.g)(3) = 195

h) (f/g)(x) = 1/3

Step-by-step explanation:

f(x) = 2x + 7, g(x) = 7x - 6

a) (f + g)(x) = f(x) + g(x) = (2x + 7) + (7x - 6)

(f + g)(x) = 9x + 1

Since x is defined for functions f & g for all real numbers, the domain of (f + g)(x) is x ε R

b) (f - g)(x) = f(x) - g(x) = (2x + 7) - (7x - 6)

(f - g)(x) = (-5x + 13)

Since x is defined for functions f & g for all real numbers, the domain of (f - g)(x) is x ε R

c) (f.g)(x) = f(x) × g(x) = (2x + 7)(7x - 6)

(f.g)(x) = 14x² - 12x + 49x - 42 = 14x² + 37x - 42

Since x is defined for functions f & g for all real numbers, the domain of (f.g)(x) is x ε R

d) (f/g)(x) = f(x)/g(x) = (2x + 7)/(7x -6)

x is defined for functions f & g for all real numbers, the domain of (f/g)(x) will be x ε R except when the denominator vanishes (that is, goes to zero). This will cause the function to take up values of ∞.

This will happen when 7x - 6 = 0, x = 6/7.

Therefore, the domain of (f/g)(x) is x ε R except the point, x = 6/7.

e) (f + g)(7) = 9(7) + 1 = 64

f) (f - g)(2) = -5(2) + 13 = 3

g) (f.g)(3) = 14(3²) + 37(3) - 42 = 195

h) (f/g)(27) = (2(27) + 7)/(7(27) - 6) = 61/183 = 1/3

Hope this Helps!!!

5 0

3 years ago

Jackie wants to learn more about local college. which of the following is a statistical question jackie could ask?

Maru [420]

The answer to this question is C

6 0

3 years ago

Read 2 more answers

A right angled triangle has sides of length 9cm, 12cm and 15cm. Calculate its area in square centimetres.

Dmitriy789 [7]

The area of a right angled triangle with sides of length 9cm, 12cm and 15cm in square centimeters is 54 sq cm.

The formula to calculate the area of a right triangle is given by:

Area of Right Triangle, A = (½) × b × h square units

Where, “b” is the base (adjacent side) and “h” is the height (perpendicular side). Hence, the area of the right triangle is the product of base and height and then divide the product by 2.

We know that the hypotenuse is the longest side. So, the area of a right angled triangle will be half of the product of the remaining two sides.

Given sides of the triangle:

a=9cm

b=12cm

c=15cm

From this we know that the hypotenuse is c. Are of the triangle will be obtained by the other two sides.

∴Area = $\frac{1}{2}$ x 9 x 12

= 54 $cm^{2}$

5 0

1 year ago

Solve the matrix equation below

Ket [755]

Answer:

We need to distribute the values
Hence [-4 0: 0 - 2 ] +[0 -3: 5 -4] X + [ 0 -3: 5 -4 ] = [19 -27 : 10 -24]

6 0

3 years ago