FOR THE FIRST PROBLEM:
Differentiating p^2 + 2q^2 = 1100 with respect to time => 2p(dp/dt) + 4q(dq/dt) = 0
<span>dp/dt = -2q/p(dq/dt) </span>
<span>R = pq </span>
<span>dR/dt = p(dq/dt) + q(dp/dt) = -p²/2q(dp/dt) + q(dp/dt) = (2q² - 1100)/2q * (dp/dt) + q(dp/dt) </span>
<span>A = (2q - 550/q)
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Answer:
Jenna needs 2 yards of ribbon to wrap 4 boxes.
Step-by-step explanation:
First, we can find how many inches of ribbon she needs.
18*4=72
She needs 72 inches of ribbon for 4 yards.
There are 36 inches in a yard.
72/36=2
Jenna needs 2 yards of ribbon to wrap 4 boxes.
Plug in the given numbers (x) to the equation.
For example, let's take the first value it gives us.
-10(-2) +y=4
20+y=4
y=-16
Then you would put that on the table, and plug in the next value(s).
Hope this helped!
4\9=.444444444
answer=choice D
Do the brackets first as it says in BIDMAS
