Answer:
y = x - 2
Step-by-step explanation:
Parallel lines have the same slope, so the line will also have a slope of 1.
Plug in the slope and given point into y = mx + b to solve for b:
y = mx + b
-1 = 1(1) + b
-1 = 1 + b
-2 = b
Plug in b and the slope into y = mx + b
y = x - 2 is the equation
Answer:
The statements that must be true are:
XY and JK form four right angles ⇒ B
XY ⊥ JK ⇒ C
JP = KP ⇒ E
m∠JPX = 90° ⇒ F
Step-by-step explanation:
From the given figure
∵ Line XY is the perpendicular bisector of the line segment JK
→ That means line XY is the line of symmetry of the line segment JK
∴ XY ⊥ JK ⇒ C
∵ XY ∩ JK at point P
∴ P is the midpoint of JK
∵ XY ⊥ JK
∴ ∠JPX, ∠KPX, ∠JPY, and ∠KPY are right angles
∴ XY and JK form four right angles ⇒ B
∵ The measure of the right angle is 90°
∴ m∠JPX = m∠KPX = m∠JPY = m∠KPY = 90°
∴ m∠JPX = 90° ⇒ F
∵ P is the midpoint of JK
∴ JP = KP ⇒ E
Im not so sure but, 3x2=6; 2x3=6; 6+6=12
The answer is d, (-2.5,0.75)
