13 is the answer if I'm correct
I don't think anyone can solve this without seeing the table mentioned in the question :)
The length
![8 \div \frac{1}{4} = 32](https://tex.z-dn.net/?f=8%20%5Cdiv%20%5Cfrac%7B1%7D%7B4%7D%20%3D%2032%20)
the width
![4 \div \frac{1}{4} = 16](https://tex.z-dn.net/?f=4%20%5Cdiv%20%5Cfrac%7B1%7D%7B4%7D%20%3D%2016)
the height
![2 \frac{1}{4} \div \frac{1}{4} \\ = \frac{9}{4} \div \frac{1}{4} = 9](https://tex.z-dn.net/?f=2%20%5Cfrac%7B1%7D%7B4%7D%20%5Cdiv%20%5Cfrac%7B1%7D%7B4%7D%20%5C%5C%20%3D%20%5Cfrac%7B9%7D%7B4%7D%20%5Cdiv%20%5Cfrac%7B1%7D%7B4%7D%20%3D%209)
so the amount of small cubes is
![32 \times 16 \times 9 = 4608](https://tex.z-dn.net/?f=32%20%5Ctimes%2016%20%5Ctimes%209%20%3D%204608)
I believe that 4608 is the answer
good luck
9514 1404 393
Answer:
= log(3888/343)
= log(3888) -log(343)
= 4·log(2) +5·log(3) -3·log(7)
≈ 1.054432
Step-by-step explanation:
Perhaps you want to simplify and evaluate the logarithm.
The applicable rules are ...
log(a/b) = log(a) -log(b)
n·log(a) = log(a^n)
__
We will use "log" for "log10". So, your logarithm can be written as ...
log(30/10) -2·log(5/9) +log(400/343)
= log(3) +log(81/25) +log(400/343)
= log(3·81·400/(25·343)) = log(3888/343)
= log(3888) -log(343)
= log(2^4·3^5) -log(7^3) = 4·log(2) +5·log(3) -3·log(7) ≈ 1.054432
_____
<em>Additional comment</em>
My personal favorite form is the log of a fraction, as it requires the fewest calculator keystrokes. Perhaps the "simplest" is the weighted sum of the logs of primes.
Answer:
a) the sample proportion planning to vote for Candidate Y is ![\frac{160}{400} =0.4](https://tex.z-dn.net/?f=%5Cfrac%7B160%7D%7B400%7D%20%3D0.4)
b) the standard error of the sample proportion is ≈ 0.024
c) 95% confidence interval for the proportion of the registered voter population who plan to vote for Candidate Y is (0.353,0.447)
d) 98% confidence interval for the proportion of the registered voter population who plan to vote for Candidate Y is (0.344,0.456)
Step-by-step explanation:
a) The sample proportion planning to vote for Candidate Y is:
![\frac{160}{400} =0.4](https://tex.z-dn.net/?f=%5Cfrac%7B160%7D%7B400%7D%20%3D0.4)
b) The standard error of the sample proportion can be found using
SE=
where
- p is the sample proportion planning to vote for Candidate Y (0.4)
- N is the sample size (400)
Then SE=
≈ 0.024
c) 95% confidence interval for the proportion of the registered voter population who plan to vote for Candidate Y can be calculated as p±z×SE where
- p is the sample proportion planning to vote for Candidate Y (0.4)
- SE is the standard error (0.024)
- z is the statistic for 95% confidence level (1.96)
Then
0.4±(1.96×0.024)=0.4±0.047 that is (0.353,0.447)
d) 98% confidence interval is similarly
0.4±(2.33×0.024)=0.4±0.056 that is (0.344,0.456) where
2.33 is the statistic for 98% confidence level.