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Nesterboy [21]
4 years ago
13

How do I solve this ?

Mathematics
1 answer:
7nadin3 [17]4 years ago
6 0
13-5 5/6
12 6/6 -5 5/6
7 1/6 is the answer to 22
25.12 1/2-6 5/8
12 4/8-6 5/8
11 12/8-6 5/8
5 7/8 is he answer to 25 
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Simplify.<br> 3 1<br> 8 8<br> OA)<br> 2<br> 1<br> B)<br> 2<br> C)<br> OD)<br> 8
lawyer [7]

Hello Love!! ♡ 

»»————-  \red{Answer\:} ————-««

\Huge{\boxed{\frac{1}{4}}}

☆♬○♩●♪✧♩ \bold{EXPLANATION\;} ♩✧♪●♩○♬☆

\mathfrak{apply~the~fraction~rule~:}~\frac{a}{c}~ -~\frac{b}{c} = \frac{a~-~b}{c}

= \frac{3-1}{8}

\mathfrak{subtract~the~numbers~:}~ 3 - 1=2

=\frac{2}{8}

\mathfrak{cancel~the~numbers~:}~\frac{2}{8} = \frac{1}{4}

=\frac{1}{4}

°:⋆ₓₒ Hope It Helps. . . ₓₒ⋆:°

Answer~:

\mathfrak{Jace}

6 0
3 years ago
Read 2 more answers
Simplify 0, -6 please :(
snow_tiger [21]

Answer:

You cant simplify it??????

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
B - (- 7) =-1<br> what is b?
irina1246 [14]

B-(-7)= -1

First negative multiply by negative is POSITIVE.

So: B+7= -1

Subtract 7 from both sides

B= -7-1

B= -8.

Answer: -8.

To Check Answer: Plug in the variable of B in the original equation.

So: -8-(-7)= -1

-8+7= -1

-1= -1

If the Solution works out the answer is right.

4 0
3 years ago
Read 2 more answers
If the sum of two numbers is 15 and their product is 50 what are they
Westkost [7]
Xy = 50
x + y = 15

x = 15 - y

xy = 50

(5 - y)y = 50

5y - y^2 = 50

y^2 - 5y + 50 = 0

(y - 5)(y - 10) = 0

y - 5 = 0 or y - 10 = 0

y = 5 or y = 10

x + y = 15

For y = 5: 

x + 5 = 15

x = 10

For y = 10

x + 10 = 15

x = 5

Answer: the numbers are 5 and 10.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=z%5E%7B7%7D%3D128i" id="TexFormula1" title="z^{7}=128i" alt="z^{7}=128i" align="absmiddle" cla
abruzzese [7]

If <em>z</em> ⁷ = 128<em>i</em>, then there are 7 complex numbers <em>z</em> that satisfy this equation.

z^7 = 128i = 2^7i = 2^7e^{i\frac\pi2}

\implies z=\sqrt[7]{2^7} e^{i\frac17\left(\frac\pi2+2n\pi\right)}

(where <em>n</em> = 0, 1, 2, …, 6)

\implies z = 2 e^{i\left(\frac\pi{14}+\frac{2n\pi}7\right)}

\displaystyle\implies z = 2 \left(\cos\left(\frac\pi{14}+\frac{2n\pi}7\right)+i\sin\left(\frac\pi{14}+\frac{2n\pi}7\right)\right)

3 0
3 years ago
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