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sergiy2304 [10]
3 years ago
11

Help, I tried! I tried using PEMDAS, but I can’t figure it out. Please explain this problem.

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
7 0

Answer:

10

Step-by-step explanation:

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x=m(y-k)^2+h\\\\(h,\ k)-the\ vertex

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x=(y-(-1))^2-4\ \ \ |+4\\\\(x+4)=(y+1)^2

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What's the circumference of a circle with a diameter of 45 centimeters
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12 divides by 4 would be 3

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In the Brady's Family, each girl has twice as many brothers as she has sisters.
levacccp [35]

Answer:

3 girls and 4 boys

Step-by-step explanation:

Writing the number of girls in the family as g and the number of boys in the family as b,

we know that each girl has twice as many brothers as sisters. Therefore, the amount of boys in the family (b, or how many brothers each girl has) is twice the number of the amount of girls in the family (g) minus 1 (g-1) (subtract 1 because each girl's number of sisters does not include the girl herself). We can write this as

b = 2(g-1)

Next,

we know that each boy has the same amount of brothers as sisters. Therefore, the amount of boys in the family minus 1 (b-1, subtracting 1 because we don't include the boy that has the brothers) is equal to the amount of girls in the family (g). we can write this as

b-1 = g

Therefore, we have

b = 2(g-1)

b-1 = g

Plugging b-1 = g into the first equation, we get

b = 2 (g-1)

2(g-1) = 2((b-1) - 1) = b

= 2(b-1-1)

= 2(b-2)

= 2b-4

b = 2b-4

subtract 2b from both sides to make it so that only b values and their coefficients are on one side

-b = -4

multiply both sides by -1 to solve for b

b=4

Therefore, there are 4 boys in the family and b-1 = 4-1 = 3 girls in the family.

3 0
3 years ago
How much more would $8,000 earn in four years compounded daily at 5% than compounded annually at 5%?
QveST [7]

Answer:

Given the statement:

8,000 earn in four years compounded daily at 5%

To find the amount we use formula:

A = P(1+\frac{r}{n})^{nt}

where P is the principal , A is the amount , n is number of times compounded per year and t is the time in year.

Here, Principal(P) = $8000, r = 5% and n = 365

Substitute these given values we get;

A_1= 8000(1+\frac{5}{365})^{365 \cdot 4}

A_1= 8000 \cdot 1.000137^{1460}

A_1= 8000 \cdot 1.22141

Simplify:

A_1= \$9771.28

To find the Interest we use formula:

I_1= A_1-P

I_1= 9771.28 -8000 = \$1771.28

It is also given that:

8,000 earn in four years compounded annually at 5%.

Here, P = $8000, r = 5% , t =4 year and n = 1

Using the same formula to calculate the amount:

A_2 = 8000(1+\frac{5}{1})^{1 \cdot 4}

A_2= 8000(1.05)^4

Simplify:

A_2= \$9724.05

To find the Interest :

I_2= A_2 - P

I_2= 9724.05 - 8000= \$1724.05

Then;

I_1-I_2 = 1771.28-1724.05 = \$47.23

Therefore, $47.23 more would  $8,000 earn in four years compounded daily at 5% than compounded annually at 5%





6 0
4 years ago
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