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Pavel [41]
3 years ago
14

Which expression is equivalent to x + 11? 11 x 11 + x 11 minus x Negative x + 11

Mathematics
1 answer:
Kitty [74]3 years ago
7 0
Imma be honest with you need a calculator not Brainly
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Which could be the area of one face of the rectangular prism? Select three options.
antiseptic1488 [7]

Answer:

44cm^2

Step-by-step explanation:

We work with area for rectangles using the face of the longer length first as this is the awkward length the perpendicular side to the easy calculation of the square and sits perpendicular to the square.

We choose the longer length and plug in and choose one of the two calculation answers.

11 x 4 = 44

11 x 6 = 66

We see the answer is 44cm^2, so we choose this one.

8 0
3 years ago
Multiply these polynomials.
maksim [4K]
When we multiply the polynomials we will get:
(5x^2+2x)(3x^2-7x+4)
=5x^2(3x^2-7x+4)+2x(3x^2-7x+4)
=15x^4-35x^3+20x^2+6x^3-14x^2+8x
=15x^4+(6x^3-35x^3)+(20x^2-14x^2)+8x
=15x^4-29x^3+6x^2+8x
The correct answer is C
4 0
3 years ago
A toy car accelerates from rest to a velocity of 4.3 m/s. It does this over a time of 4 seconds. What is the car's acceleration?
Oxana [17]

Answer:

it will be 8.3 seconds try to add

4 0
3 years ago
Suppose that from the past experience a professor knows that the test score of a student taking his final examination is a rando
DENIUS [597]

Answer:

n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable who represents the test score of a student taking his final examination. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =73,\sigma =10.5)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

We want to find the value of n that satisfy this condition:

P(71.5 < \bar X

And we can use the z score formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we have this:

P(\frac{71.5-73}{\frac{10.5}{\sqrt{n}}} < Z

And we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=0.94

And by properties of the normal distribution we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=1-2P(Z

If we solve for P(Z we got:

P(Z

Now we can find a quantile on the normal standard distribution that accumulates 0.03 of the area on the left tail and this value is: z=-1.881

And using this we have this equality:

-1.881 = -0.14286 \sqrt{n}

If we solve for \sqrt{n} we got:

\sqrt{n} = \frac{-1.881}{-0.14286}=13.167

And then n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

6 0
3 years ago
I have 30 photos to post on my website. I'm planning to post these on two web pages, one marked "Friends" and the other marked "
Sergio039 [100]

Answer:a) 870

b) 435

Step-by-step explanation:

a)

number of photos to be posted =n = 30

number of web pages on which they would be posted is 2

Since the order in which the photos appear on the web pages matters,

Number of ways = 30 permutation 2

=870 ways

b)

Since the order in which the photos appear on the web pages does not matter,

Number of ways = 30 combination 2

= 435 ways

6 0
3 years ago
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