Answer:
A) 0
Step-by-step explanation:
got right on assignment
Answer:
24 Domain: s>=2 or s<=-2
25. 3x^2 +14x +10
26. x^2 -2x+5
Step-by-step explanation:
24. Domain is the input or s values
square roots must be greater than or equal to zero
s^2-4 >=0
Add 4 to each side
s^2 >=4
Take the square root
s>=2 or s<=-2
25. f(g(x)) stick g(x) into f(u) every place you see a u
f(u) = 3u^2 +2u-6
g(x) = x+2
f(g(x) = 3(x+2)^2 +2(x+2) -6
Foil the squared term
= 3(x^2 +4x+4) +2x+4-6
Distribute
= 3x^2 +12x+12 +2x+4-6
Combine like terms
=3x^2 +14x +10
26 f(g(x)) stick g(x) into f(u) every place you see a u
f(u) = u^2+4
g(x) = x-1
f(g(x) = (x-1)^2 +4
Foil the squared term
= (x^2 -2x+1) +4
= x^2 -2x+5
Answer:
72 mles
Step-by-step explanation:
For better understanding, I'll make use of an attachment.
From the attachment,
O represents the start point
--- Jack
-- Distance between them
Required
Find OA; Jack's distance
To do this, we make use of Pythagoras theorem
This gives:
Subtract 900 from both sides
Take square roots
<em>Hence, Jill drove 72 miles</em>
9/12 chose Friday or Saturday. That reduces to 3/4. Which is also 75%. Hope that helps.
Answer:
f¯¹(x) = 23/ (6x + 3)
Step-by-step explanation:
f(x) = (23 – 3x)/6x
The inverse, f¯¹, for the above function can be obtained as follow:
f(x) = (23 – 3x)/6x
Let y be equal to f(x)
Therefore, f(x) = (23 – 3x)/6x will be written as:
y = (23 – 3x)/6x
Next, interchange x and y.
This is illustrated below:
y = (23 – 3x)/6x
x = (23 – 3y)/6y
Next, make y the subject of the above expression. This is illustrated below:
x = (23 – 3y)/6y
Cross multiply
6xy = 23 – 3y
Collect like terms
6xy + 3y = 23
Factorise
y(6x + 3) = 23
Divide both side by (6x + 3)
y = 23/ (6x + 3)
Finally, replace y with f¯¹(x)
y = 23/ (6x + 3)
f¯¹(x) = 23/ (6x + 3)
Therefore, the inverse, f¯¹, for the function f(x) = (23 – 3x)/6x is
f¯¹(x) = 23/ (6x + 3)
