When the penny hits the ground, h will = 0.
So: Set h(t) = 0 = -4.9t^2 + 0t + 150 m
Then 4.9t^2 = 150, and so t^2 = sqrt(150 / 4.9) = plus or minus 5.53 sec.
We can use only the positive root, as we're measuring time.
t = 5.5 sec (answer)
<h3>Given</h3>
A(-3, 1), B(4, 5)
<h3>Find</h3>
coordinates of P on AB such that AP/PB = 5/2
<h3>Solution</h3>
AP/PB = 5/2 . . . . . desired result
2AP = 5PB . . . . . . multiply by 2PB
2(P-A) = 5(B-P) . . . meaning of the above
2P -2A = 5B -5P . . eliminate parentheses
7P = 2A +5B . . . . . collect P terms
P = (2A +5B)/7 . . . .divide by the coefficient of P
P = (2(-3, 1) +5(4, 5))/7 . . . . substitute the given points
P = (-6+20, 2+25)/7 . . . . . . simplify
P = (2, 3 6/7)
I think we have to see the image to answer you question
I think it might be 40 I’m not sure but good luck
Answer:
A.) The graph of g(x) is the graph of f(x) expanded vertically by a factor of 2, and translated 6 unit(s) up.
Step-by-step explanation:
For vertical expansion by a scale factor of k, the graph of f(x) is transformed to ...
g(x) = k·f(x)
For translation up by k units, f(x) is transformed to ...
g(x) = f(x) +k
___
Comparing the following ...
f(x) = log(x)
g(x) = 2·log(x) +6
We see that a multiplication factor and an addition factor have been applied. That means ...
g(x) is f(x) expanded vertically by a factor of 2, and translated up 6 units.
