Y=X/5
Step-by-step explanation:
Step 1:
Let X be the input and Y be the output variable
Given: the output is one-fifth of the input
Step 2:
Y=X/5 be the require function
Eq:
for X=1, Y = 1/5
X=2, Y=2/5, etc
Answer:
the answer would be she would drive 192 miles
You just need to plot them on a graph and see how many spaces are in between each. So if you plot (1,9) remember it's X, Y axis. Start from zero on the graph. Since it's positive go over 1 to the right and up 9. Then do the same for the rest. Then count how many units are between each point on the graph and find the one that is 5 units apart.
Answer:
(x, y, z) = (6, 7, 6)
Step-by-step explanation:
Maybe your matrix is ...
![\left[\begin{array}{ccc|c}3& -1& 7& 53\\ 1& 7& 1& 61\\ 9& 1&1&67\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D3%26%20-1%26%207%26%2053%5C%5C%201%26%207%26%201%26%2061%5C%5C%209%26%201%261%2667%5Cend%7Barray%7D%5Cright%5D)
A calculator can tell you the solution is ...
(x, y, z) = (6, 7, 6)
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For systems of equations in more than 2 variables the third variable can be defined in terms of the other two (as for solution by substitution). This can be substituted into the remaining equations to obtain two equations in two unknowns. That solution can then be used to find the value of the third variable. The attachment shows application of this method.
We used the last equation to define z, then used that definition in the first two equations. The same approach can be used for an algebraic solution.
The solution is (x, y, z) = (6, 7, 6).