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Vitek1552 [10]
3 years ago
6

One number is 4 less than a second number. Twice the second number is 13 less than 5 times the first. Find the two numbers.

Mathematics
1 answer:
Roman55 [17]3 years ago
3 0

Answer:

7 , 11

Step-by-step explanation:

Let the second number be 'x'

the first number = x - 4

Twice the second number : 2*x = 2x

5times first = 5*(x -4) = 5*x - 5*4 = 5x - 20

13 less than 5 times the first = 5x - 20 - 13 = 5x - 33

5x - 33 = 2x

Add 33 to both sides

5x - 33 + 33 = 2x +33

5x = 2x + 33

Subtract '2x'from both sides

5x - 2x = 2x - 2x + 33

3x = 33

Divide both sides by 3

\frac{3x}{3}=\frac{33}{3}

x = 11

First number = x - 4 = 11 - 4 = 7

The numbers are 7 , 11

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horrorfan [7]

Answer:

The equation relating the volume of water, y to the volume of flour, x is therefore;

y = 1/3×x

The quantity of water per liter of flour = 1/3 liters

The quantity of flour per liter of water = 3 liters

Step-by-step explanation:

The given information from the graph are;

At 0 liters of water, the volume of flour = 0 liters of flour

At 1 liter of water, the volume of flour = 3 liters of flour

The relationship between the volume of water and flour is linear given s follows;

The equation for a linear relationship is y = m·x + c

m = The gradient or slope of the line, c = the y-intercept

In the graph the y-intercept = 0 therefore, c = 0

The slope, m is (change in y-coordinate)/(Change in x-coordinate)

∴ m = (1 - 0)/(3 - 0) = 1/3

The equation relating the volume of water, y to the volume of flour, x is therefore;

y = 1/3×x

Such that when the question asks, how many liter of water is used per liter of flour, we get;

y = 1/3× 1 = 1/3 liters

Similarly when the question asks, how many liter of flour is used per liter of water, we get;

1 = 1/3×x

x = 3 × 1 = 3 liters.

4 0
3 years ago
How to write 12/5 as a mixed number
Marat540 [252]

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
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False this value is very likely to find in this distribution

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With mean 7 ( μ ) and standad deviation  (σ ) 2 we can observe, value 6.6  is close to the lower limit of the interval

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