I = PRT
14,300 = (700)(0.0725)(t)
14,300 = 50.75(t)
14300/50.75 = t
281.77 = t or t = 281.77
hope this helps :)
1. If the matching ends are triangles, find the area of the triangle (A=1/2bh)
2. If Matching ends are rectangles/squares, find the area of the rectangle/square (bh)
Hope that was helpful!!!
9514 1404 393
Answer:
72
Step-by-step explanation:
The triangles are said to be similar. (ΔNPQ ~ ΔRSQ) That means corresponding sides have the same ratio:
NP/RS = NQ/RQ = PQ/SQ = 24/32 = 21/28 = 3/4
This ratio, or scale factor, also applies to the perimeters of the two triangles.
perimeter NPQ / perimeter RSQ = 3/4
Using the given expressions for the perimeters, we have ...
(7x +2)/(10x -4) = 3/4
We can solve this equation in the usual way to find the value of x. Then we can use that value to find the perimeter of ΔNPQ.
4(7x +2) = 3(10x -4) . . . . . multiply both sides by 4(10x -4)
28x +8 = 30x -12 . . . . . eliminate parentheses
20 = 2x . . . . . . . . . . . add 12-28x to both sides
10 = x . . . . . . . . . . . divide both sides by 10
The perimeter of ΔNPQ is ...
7x +2 = 7(10) +2 = 72
The perimeter of triangle NPQ is 72 units.

- Find square root of 144 by factorisation method.

We can find the square root of 144 using the factorisation method. In this method, you need to factorise 144 first. Then, you'll get your answer in the form of prime factors. In this case, it's ⇨ 2 × 2 × 2 × 2 × 3 × 3.
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To find the square root using factorisation, we need to group the same number in pairs. That is, 2 × 2 × 2 × 2 × 3 × 3 by grouping same numbers in pairs will become ⇨ (2, 2), (2, 2), (3, 3).
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Now, you should take only 1 of the number from these groups. So, (2, 2), (2, 2), (3, 3) will change to ⇨ 2 × 2 × 3.
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Finally, just multiply this set of numbers to find the square root of 144. 2 × 2 × 3 = 4 × 3 =
⇨ square root of 144.
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- The square root of 144 is <em><u>1</u></em><em><u>2</u></em><em><u>.</u></em>
Yo sup??
the angle is in 3rd quadrant.
we can say that
sin(90+150)
=sin(180+60)
=-sin(60)
=-3^(1/2)/2
Hence the correct answer is option A
Hope this helps