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lord [1]
3 years ago
15

Please answer the question correctly while showing detailed working. ​

Mathematics
2 answers:
AfilCa [17]3 years ago
7 0

Answer: 2

Step-by-step explanation:

8^2x+1 / 8^2 = 8^3

8^2x+1  = 8^5

2x+1= 5

2x= 4

x= 2

algol133 years ago
7 0

\\ \sf\longmapsto \dfrac{8^{2x+1}}{64}=8^3

\\ \sf\longmapsto \dfrac{8^{2x+1}}{8^2}=8^3

  • a^m÷a^n=a^{m-n}

\\ \sf\longmapsto 8^{2x+1-2}=8^3

\\ \sf\longmapsto 8^{2x-1}=8^3

\\ \sf\longmapsto 2x-1=3

\\ \sf\longmapsto 2x=3+1

\\ \sf\longmapsto 2x=4

\\ \sf\longmapsto x=\dfrac{4}{2}

\\ \sf\longmapsto x=2

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A set of equations is given below:
Zanzabum
The answer is:  [A]:  "No solution" .
_______________________________________________
Note:  Given:
_______________________________________________
  y = 4x + 8 ;
  y = 4x + 2 ;
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Since:  "y = y" ;

4x + 8 = 4x + 2 ; which is not true;
______________________________
 4x  +  8  ≠  4x  +  2 ;  since,  "8  ≠ 2" ;

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→ Subtract "4x" from each side of the equation:

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 " 8 = 2 " ;  not true ; since  "8 ≠ 2" ;
______________________________
Also, suppose:
_______________________________
 4x + 8 = 4x + 2 ;

→ Subtract "2" from BOTH SIDES of the equation;

4x + 8 − 2 = 4x + 2 − 2 ;

to get:

4x + 6 = 4x

(Note:  "4x + 0 = 4x" ;  but "4x + 6 ≠ 4x") l

But even if we have:

4x + 6 = 4x ;

→ Subtract "4x" from EACH side of the equation:

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   6 = 0 ; which is not true;  "6 ≠ 0" . 
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The correct answer is:  [A]:  "No solution" .
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