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2 years ago

Please answer the question correctly while showing detailed working.

Mathematics

2 answers:

AfilCa [17]2 years ago

7 0

Answer: 2

Step-by-step explanation:

8^2x+1 / 8^2 = 8^3

8^2x+1 = 8^5

2x+1= 5

2x= 4

x= 2

algol132 years ago

7 0

$\\ \sf\longmapsto \dfrac{8^{2x+1}}{64}=8^3$

$\\ \sf\longmapsto \dfrac{8^{2x+1}}{8^2}=8^3$

a^m÷a^n=a^{m-n}

$\\ \sf\longmapsto 8^{2x+1-2}=8^3$

$\\ \sf\longmapsto 8^{2x-1}=8^3$

$\\ \sf\longmapsto 2x-1=3$

$\\ \sf\longmapsto 2x=3+1$

$\\ \sf\longmapsto 2x=4$

$\\ \sf\longmapsto x=\dfrac{4}{2}$

$\\ \sf\longmapsto x=2$

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Suppose a parabola has vertex (6,5) and also passes through the point (7,7). Write the equation of the parabola in vertex form.

jek_recluse [69]

Answer:

Choice B: $y = 2\, (x - 6)^{2} + 5$ .

Step-by-step explanation:

For a parabola with vertex $(h,\, k)$ , the vertex form equation of that parabola in would be:

$\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}$ .

In this question, the vertex is $(6,\, 5)$ , such that $h = 6$ and $k = 5$ . There would exist a constant $a$ such that the equation of this parabola would be:

$y = a\, (x - 6)^{2} + 5$ .

The next step is to find the value of the constant $a$ .

Given that this parabola includes the point $(7,\, 7)$ , $x = 7$ and $y = 7$ would need to satisfy the equation of this parabola, $y = a\, (x - 6)^{2} + 5$ .

Substitute these two values into the equation for this parabola:

$7 = (7 - 6)^{2}\, a + 5$ .

Solve this equation for $a$ :

$7 = a + 5$ .

$a = 2$ .

Hence, the equation of this parabola would be:

$y = 2\, (x - 6)^{2} + 5$ .

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3 years ago

I will Give you Brainliest b^(2)-c^(2)-10(b-c)

Hitman42 [59]

Answer:

b^2-c^2-10b+10c

Step-by-step explanation:

b^2-c^2-10(b-c)

b^2-c^2-10b+10c

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marishachu [46]

Answer:

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Step-by-step explanation:

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2 years ago

Suppose that prices of recently sold homes in one neighborhood have a mean of $265,000 with a standard deviation of $9300. Using

Hatshy [7]

Answer:

Range = (237100, 292900)

Step-by-step explanation:

Using Chebyshevs Inequality:

$P(|X - \mu | \le k \sigma )\ge 1 -\dfrac{1}{k^2}= 0.889$

$1 -\dfrac{1}{k^2}= 0.889$

$\dfrac{1}{k^2}= 1- 0.889$

$\dfrac{1}{k^2}=0.111$

$k = \sqrt{\dfrac{1}{0.111}}$

$k \simeq 3$

Thus, 88.9% of the population is within 3 standard deviation of the mean with the Range = μ ± kσ

where;

μ = 265000

σ = 9300

Range = 265000 ± 3(9300)

Range = 265000 ± 27900

Range = (265000 - 27900, 265000 + 27900)

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2 years ago

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NISA [10]

1. a

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3 years ago

Read 2 more answers

Please answer the question correctly while showing detailed working. ​

Please answer the question correctly while showing detailed working.