If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
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Answer:
Ele não distribuiu corretamente
Step-by-step explanation:
3+2 x20
3+2=5
5x20=
100
Hope this helped.
Answer:
Original price reduced by 30%
Step-by-step explanation:
You want the deepest discount, which means you want the greatest percent/amount off. The first choice is 20%. The second is 30%. The third one is 25%, because you are paying for 75% (100-75). The second choice offers the deepest discount because it is 30% off.
Answer:
0.83,0.50
Step-by-step explanation:
Since there are 2 digits in 83, the very last digit is the "100th" decimal place.
So we can just say that .83 is the same as 83/100.
So your final answer is: .83 can be written as the fraction