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vladimir2022 [97]
3 years ago
14

Sammy has $180 in her savings account and plans to deposit $20 each month.help me plz ​

Mathematics
1 answer:
Gemiola [76]3 years ago
5 0

Answer:

For a function f(x) = y.

The independent variable is the one that we chose to input in the function, in this case, is x, and the dependent variable is the variable that changes in response to the independent variable, in this case, is y.

In this problem we have:

"Sammy has $180 in her savings account and plans to deposit $20 each month."

We can define:

y = money in her savings account

x = number of months that have been passed since she started saving.

Originally, she has $180, and she saves $20 per month, so if x months have been passed, the total amount of money in her savings account is:

y = f(x) = $180 + $20*x

Now we want to know if this function is continuous or discrete, to see this we need to look at the possible values of x.

x represents the number of months that have been passed, then the values that x can take are:

x = 0, 1, 2, 3, 4, ...

So x can only take the values of positive integers, this means that the domain of x is discrete, then the function f(x) is a discrete function.

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Given: FPST is a trapezoid, FP=ST, m∠F=45°, PF=8, PS=10 <br><br> Find: The midsegment MN.
kodGreya [7K]

Answer:

4\sqrt{2}+10

Step-by-step explanation:

In trapezoid FPST, FP=ST, then this trapezoid is isosceles, so

m\angle F=m\angle T=45^{\circ}.

Draw the height PH. Triangle FPH is right triangle with two angles of measure 45°. This means that FH=HP. By the Pythagorean theorem,

FH^2+PH^2=PF^2,\\ \\2FH^2=8^2,\\ \\FH^2=32,\\ \\FH=4\sqrt{2}.

Since trapezoid FPST is isosceles, the base FT hasthe length

FT=2FH+PS=8\sqrt{2}+10.

Then the length of the midline is

MN=\dfrac{FT+PS}{2}=\dfrac{8\sqrt{2}+10+10}{2}=4\sqrt{2}+10.

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3 years ago
Y varies inversely with x. If y = 5 when x = 60, find y when x = 150
andreev551 [17]

Answer:

y =2 when x = 150

Step-by-step explanation:

Inverse variation is

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150y = 300

Divide by 150

150y/150 = 300/150

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