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Mekhanik [1.2K]
3 years ago
11

Solve the system by graphing. Write the solution as an ordered pair. y = 1/3x + 2 y = –x – 2

Mathematics
1 answer:
Dima020 [189]3 years ago
4 0
ANSWER

The solution is where the two graphs intersect, which is
(-3,1).

EXPLANATION

The given system of equations are
y = \frac{1}{3} x + 2
and

y = - x - 2

We need to graph the two equations.

Let us graph

y = \frac{1}{3} x + 2
first.

We need at least two points.

You can choose any appropriate value for x and solve for y. Choosing zero makes our working easier. So let us plot the intercepts.

When
x = 0

\Rightarrow \: y = \frac{1}{3} (0) + 2

\Rightarrow y = 0 + 2

\Rightarrow y = 2

So this gives us the ordered pair,

(0,2)

When
y = 0
we get,

0= \frac{1}{3} x + 2

\Rightarrow \: - 2 = \frac{1}{3} x

\Rightarrow \: - 2 \times 3= x

\Rightarrow \: -6= x
This also gives the ordered pair

(-6,0).

We plot these two points and draw a straight line through them to obtain the blue graph in the attachment.

For the second line

y = - x - 2

We again find the intercepts and plot them.

When
x = 0

y = - 0 - 2

\Rightarrow \: y = - 2

This gives the ordered pair

(0,-2)

Also, when
y = 0

then we have,

0 = - x - 2

2 = - x

x = - 2

Then we again have the ordered pair,

(-2,0)

We plot these two points on the same graph sheet to obtain the red graph above.

The intersection of the two lines is
(-3,1)


You will get good grades so don't worry much.

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Plsss help no one answered the other times I put this question
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Answer:

a) <em>The equation</em> (10s + 8w) <em>represents </em><em>the </em><em>calories </em><em>Bridget </em><em>ate </em><em>on </em><em>Monday </em><em>and </em><em>the </em><em>equation</em> (20s + w) <em>represents </em><em>the </em><em>calories</em><em> </em><em>she </em><em>ate</em><em> </em><em>the </em><em>next </em><em>day.</em>

<em>b)</em><em> </em><em>The </em><em>number </em><em>of </em><em>calories</em><em> </em><em>in </em><em>each </em><em>strawberry</em><em> </em><em>is </em>4 <em>and </em><em>the </em><em>number </em><em>of </em><em>calories </em><em>in </em><em>each </em><em>vanilla</em><em> </em><em>wafer</em><em> cookie</em><em> </em><em>is </em>19. The solution is s= 4 and w = 19.

Step-by-step explanation:

For part A, Bridget ate 10 strawberries and 8 vanilla wafer cookies on Monday. Since the the number of calories in a strawberry is <em>s</em> and the number of calories in a vanilla wafer cookie is <em>w </em>, the number of calories Bridget ate on Monday is <em>10s + 8w</em><em>.</em><em> </em>The next day, Bridget ate 20 strawberries and 1 vanilla wafer cookie. Hence, the number of calories Bridget ate on the next day is 20s<em> + w</em>.

For part B,

we will create two different simultaneous equations.

Equation 1: 10s + 8w = 192

Equation 2: 20s + w = 99

We need to find one of the terms first to solve the other term. For this case, I will solve for w first.

Multiply the first equation by 2.

Equation 3: 20s + 16w = 192*2 = 384.

Now, subtract equation 2 from this new equation.

Equation 4:

(20s + 16w) - (20s + w) = 384 - 99

20s + 16w - 20s - w = 285

15w = 285

This leaves only w left and we can solve w.

w = 285 / 15 = 19

Now, we can solve for s using equation 2.

20s + 19 = 99

20s = 99-19 = 80

Hence,

s = 80/20 = 4

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Answer:

Brian's average speed: 14.73 mile/hour

The traveled distance by skiing he estimated: 11.0475 miles.

As the information provided in table, the time he spent for skiing is 0.75

=> The distance Brian traveled by skiing: 14.73 x 0.75 = 11.0475 (miles)

=> Brian's product is correct.

=> Rounding to the nearest whole number => 11.0475 = 11 (miles)

Rounding the Brian's average speed to the nearest whole number:

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Hope this helps!

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Answer:

<h2><em>2ft by 2ft by 1 ft</em></h2>

Step-by-step explanation:

Total surface of the cardboard box is expressed as S = 2LW + 2WH + 2LH where L is the length of the box, W is the width and H is the height of the box. Since the cardboard box is without a lid, then the total surface area will be expressed as;

S  = lw+2wh+2lh ... 1

Given the volume V = lwh = 4ft³ ... 2

From equation 2;

h = 4/lw

Substituting into r[equation 1;

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Differentiating the resulting equation with respect to w and l will give;

dS/dw = l + (-8w⁻²)

dS/dw = l - 8/w²

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dS/dw = w - 8/l²

At turning point, ds/dw = 0 and ds/dl = 0

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l = l⁴/8

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2 = 8/w²

1 = 4/w²

w² = 4

w = 2 ft

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4 = 2(2)h

4 = 4h

h = 1 ft

Height of the cardboard is 1 ft

<em>The dimensions of the box that requires the least amount of cardboard is 2ft by 2ft by 1 ft</em>

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Answer:

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