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2 years ago

Unit #2 - Lesson #7 Exit Ticket: Solve the equation shown below for the variable x. Place your answer in the answer box.

Mathematics

1 answer:

jolli1 [7]2 years ago

7 0

Answer:

$x = bc + 2b$

PLEASE MARK ME AS BRAINLIEST

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How do I solve 27×36

Fudgin [204]

Answer:

972

Step-by-step explanation:

so you put it up and down 72

x 36

and you x 6 and 2 and 6 and 7

and you do the same with the 3

3x2 and 3x7

4 0

3 years ago

Read 2 more answers

supervisor records the repair cost for 25 randomly selected dryers. A sample mean of $93.36 and standard deviation of $19.95 are

Simora [160]

<h2>Answer with explanation:</h2>

The confidence interval for population mean (when population standard deviation is unknown) is given by :-

$\overline{x}-t^*\dfrac{s}{\sqrt{n}}< \mu$

, where n= sample size

$\overline{x}$ = Sample mean

s= sample size

t* = Critical value.

Given : n= 25

Degree of freedom : $df=n-1=24$

$\overline{x}= \$93.36$

$s=\ $19.95$

Significance level for 98% confidence interval : $\alpha=1-0.98=0.02$

Using t-distribution table ,

Two-tailed critical value for 98% confidence interval :

$t^*=t_{\alpha/2,\ df}=t_{0.01,\ 24}=2.4922$

⇒ The critical value that should be used in constructing the confidence interval = 2.4922

Then, the 95% confidence interval would be :-

$93.36-(2.4922)\dfrac{19.95}{\sqrt{25}}< \mu$

$=93.36-9.943878< \mu$

$=83.416122< \mu$

Hence, the 98% confidence interval for the mean repair cost for the dryers. = $83.4161$

4 0

2 years ago

Find the area of the composite figure below.

daser333 [38]

Answer:

112

Step-by-step explanation:

srry. i meant to put 112 erlier

3 0

2 years ago

The composite shape is made up of two different rectangles and two different triangles. What is the area of the composite shape

Rus_ich [418]

Answer:

43 unit²

Step-by-step explanation:

Sorry for the bad handwriting ;-;

7 0

1 year ago

Logarithms:

WITCHER [35]

Answer:

A) k = 18.75
B) R(0.8) = 161419
C) R(0.3) = 275

Step-by-step explanation:

Given expression

R(x) = 6*e^(kx)

A) Given

x = 0.04
R = 10

Solving for k

10 = 6*e^(0.04k)
e^(0.04k) = 10/6
ln (e^0.04k) = ln (1.6666)
0.04k = 0.51
k = 0.51/0.04
k = 12.75

B) Given

x = 0.8
R= ?

The value of R(0.8) is:

R(0.8) =
6*e^(0.8*12.75) =
6*e^(10.2) =

161419 rounded

C) Given

x = 0.3
R = ?

The value of R(0.3) is:

R(0.3) =
6*e^(0.3*12.75) =
6*e^(3.825) =

275 rounded

4 0

3 years ago

Unit #2 - Lesson #7 Exit Ticket: Solve the equation shown below for the variable x. Place your answer in the answer box.​

Unit #2 - Lesson #7 Exit Ticket: Solve the equation shown below for the variable x. Place your answer in the answer box.