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3 years ago

Graph the intercept. What are points?

Mathematics

1 answer:

Airida [17]3 years ago

6 0

Answer:

start at 0 and go up 3 and put a point (your x)

start at 0 and also go up 5 and put a point (your y)

draw LINE HORIZONALY ACROSS THE (LEFT TO RIGHT ) on each line

you should have two horizonal lines parallel

Step-by-step explanation:

You might be interested in

Soil sells for 8 1/4 cents per pound. How much would you save if you bought a 100- pound sack for $7.45?

asambeis [7]

Answer:

$0.80

Step-by-step explanation:

If the 100 pounds was bought separately (of course in real life you will probably not)

= 100 pounds x $0.0825/pound

= $8.25

As you can see it will cost more than if you buy a 100 pound sack.

Cost Difference = $8.25 - $7.45 = $0.80

That means you will save $0.80 from it.

4 0

2 years ago

Me dicen la sifra 5p-14=8p+19

Alex

5p-14=8p+19
8p-5p = -3p
-3p-14=18
14+18 = 33
33/-3=-11

7 0

3 years ago

X^3 + ax^2 +2ax + 5 divided by x + 1 what is the value of a

svlad2 [7]

5 0

3 years ago

A researcher wishes to estimate the average blood alcohol concentration (BAC) for drivers involved in fatal accidents who are f

Mnenie [13.5K]

Answer:

A 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

Step-by-step explanation:

We are given that a researcher randomly selects records from 60 such drivers in 2009 and determines the sample mean BAC to be 0.16 g/dL with a standard deviation of 0.080 g/dL.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean BAC = 0.16 g/dL

s = sample standard deviation = 0.080 g/dL

n = sample of drivers = 60

$\mu$ = population mean BAC in fatal crashes

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 90% confidence interval for the population mean, $\mu$ is;

P(-1.672 < $t_5_9$ < 1.672) = 0.90 {As the critical value of t at 59 degrees of

freedom are -1.672 & 1.672 with P = 5%} P(-1.672 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.672) = 0.90

P( $-1.672 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.672 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.672 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.672 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.672 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.672 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $0.16-1.672 \times {\frac{0.08}{\sqrt{60} } }$ , $0.16+1.672 \times {\frac{0.08}{\sqrt{60} } }$ ]

= [0.143, 0.177]

Therefore, a 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

7 0

4 years ago

1/2(2-4x)+2x=13 What is x I need a step by step

Ilya [14]

Answer:

x=3

Step-by-step explanation:

1/2(2-4x)+2x=13

1-2x+2x=13

4x=13-1

x=12/4

x=3

3 0

4 years ago