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Lemur [1.5K]
3 years ago
10

Arun’s restaurant bill is $58, and he wants to leave the waiter an 18 percent tip. What will Arun’s total bill be?

Mathematics
2 answers:
Tatiana [17]3 years ago
8 0

Answer:

$68.44

Step-by-step explanation:

Natalka [10]3 years ago
6 0

Answer:

68.44

Step-by-step explanation:


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Question<br> What is the factored form of this polynomial?<br> p(x) = x + 7x2 + 4x - 12
Soloha48 [4]

Answer:

^(3)+7x^(2)+4x-12

Step-by-step explanation:

8 0
3 years ago
The combined weight of the people in an elevator is 49% of the 3,025-pound capacity.Which would be the best way to estimate the
klasskru [66]

Answer:

50% of 3000

Step-by-step explanation:

49% is very close to 50% (half).  3,025 pounds is very close to 3,000 pounds.

Half of 3,000 pounds is 1,500 pounds.

3 0
2 years ago
Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^
Gemiola [76]

Answer:

\rm \displaystyle y' =   2 {e}^{2x}   +    \frac{1}{x}  {e}^{2x}  + 2 \ln(x) {e}^{2x}

Step-by-step explanation:

we would like to figure out the differential coefficient of e^{2x}(1+\ln(x))

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

\displaystyle y =  {e}^{2x}  \cdot (1 +   \ln(x) )

to do so distribute:

\displaystyle y =  {e}^{2x}  +   \ln(x)  \cdot  {e}^{2x}

take derivative in both sides which yields:

\displaystyle y' =  \frac{d}{dx} ( {e}^{2x}  +   \ln(x)  \cdot  {e}^{2x} )

by sum derivation rule we acquire:

\rm \displaystyle y' =  \frac{d}{dx}  {e}^{2x}  +  \frac{d}{dx}   \ln(x)  \cdot  {e}^{2x}

Part-A: differentiating $e^{2x}$

\displaystyle \frac{d}{dx}  {e}^{2x}

the rule of composite function derivation is given by:

\rm\displaystyle  \frac{d}{dx} f(g(x)) =  \frac{d}{dg} f(g(x)) \times  \frac{d}{dx} g(x)

so let g(x) [2x] be u and transform it:

\displaystyle \frac{d}{du}  {e}^{u}  \cdot \frac{d}{dx} 2x

differentiate:

\displaystyle   {e}^{u}  \cdot 2

substitute back:

\displaystyle    \boxed{2{e}^{2x}  }

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

\displaystyle  \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)

let

  • f(x) \implies   \ln(x)
  • g(x) \implies    {e}^{2x}

substitute

\rm\displaystyle  \frac{d}{dx}  \ln(x)  \cdot  {e}^{2x}  =  \frac{d}{dx}( \ln(x) ) {e}^{2x}  +  \ln(x) \frac{d}{dx}  {e}^{2x}

differentiate:

\rm\displaystyle  \frac{d}{dx}  \ln(x)  \cdot  {e}^{2x}  =   \boxed{\frac{1}{x} {e}^{2x}  +  2\ln(x)  {e}^{2x} }

Final part:

substitute what we got:

\rm \displaystyle y' =   \boxed{2 {e}^{2x}   +    \frac{1}{x}  {e}^{2x}  + 2 \ln(x) {e}^{2x} }

and we're done!

6 0
3 years ago
The function f(t) = 3(1 + 0.5)^nt models the weight in pounds of an alligator each year from its birth. Based on the function, w
masha68 [24]
<h2>Hello!</h2>

The answer is: 50% (0.5)

<h2>Why?</h2>

Exponential growth equations are use to predict the growth (in function of time) using proportional information.

We can calculate the exponential growth using the following formula:

y=S(1+r)^{t}

Where,

S, is the starting value

r, is the growth rate

t, is the time

So, we are given the function:

f(t) = 3(1 + 0.5)^{nt}

Where,

f(t), is the function,

3, is the starting value (lb)

0.5 (50%) is the growth rate

nt, is the time elapsed.

Hence,

From the given function, we know that the growth rate is equal to 0.5, and it's equal to 50%.

We can turn the growth rate given in real numbers to percent value by multiplying by 100

GrowthRate(Percentage)=0.5*100=50(Percent)

So, the growth rate is 50%.

Have a nice day!

5 0
3 years ago
PLEASE HELP I WILL PUT MORE QUESTIONS IN COMMENTS
just olya [345]
3610.201 this the answer if u want in de imal
8 0
3 years ago
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