Answer:
The perimeter of triangle PQR is 17 ft
Step-by-step explanation:
Consider the triangles PQR and STU
1. PQ ≅ ST = 4 ft (Given)
2. ∠PQR ≅ ∠STU (Given)
3. QR ≅ TU = 6 ft (Given)
Therefore, the two triangles are congruent by SAS postulate.
Now, from CPCTE, PR = SU. Therefore,
Now, side PR is given by plugging in 3 for 'y'.
PR = 3(3) - 2 = 9 - 2 = 7 ft
Now, perimeter of a triangle PQR is the sum of all of its sides.
Therefore, Perimeter = PQ + QR + PR
= (4 + 6 + 7) ft
= 17 ft
Hence, the perimeter of triangle PQR is 17 ft.
I believe it would be Steel so B
9 + 5 + 4 + 7 = 25
Ratio = 5 : 25
Ratio = 1 : 5 <==== answer
A=2πrh+2πr2=2·π·6·25+2·π·6^2 so the answer is D
Answer: 16/81 (x-10)^2 -4
Step-by-step explanation:
To write a vertex equation with just a point and the vertex, you have to figure out the variables.
In vertex form, the equation is y = a (x-h)^2 + k
Your y is 12, x = 1, h = 10, and k = -4
Plug everything into equation
12 = a (1 - 10)^2 -4
12 = a (-9)^2 - 4
12 = 81a - 4
16 = 81a
16/81 = a
Now you know what the 'a' value is.
If you graph 16/81 (x-10)^2 -4 , you will get a point at (1,12) and a vertex of (10,-4)!
I hope this helps!
