Answer:
7.3
Step-by-step explanation:
For this question, you must use the distance formula. The distance formula is based around Pythagorean Theorem, so you will see some similarities.
Distance = 
X2 is 7 (X coordinate of school)
X1 is 5 (X coordinate of friend's house)
7 - 5 = 2
2^2 = 4
Y2 is 7 (Y coordinate of school)
Y1 is 0 (Y coordinate of friend's house)
7 - 0 = 7
7^2 = 49
4 + 49 = 53
= 7.2801...
<em>Round to the nearest tenth...</em>
<em>7.3</em>
Answer:
— 4√16(cos(4π3)+isin(4π3))=2(cos(−π6)+isin(−π6))=√3−i. Explanation: De Moivre's formula tells us that: (cosθ+isinθ)n=cosnθ+isinnθ.
Step-by-step explanation:
Answer:
2 * 2 * 2 * 2 * 5.
Step-by-step explanation:
The given quadrilateral ABCD is a parallelogram since the opposite sides are of same length AB and DC is 4 and AD and BC is 2.
<u>Step-by-step explanation</u>:
ABCD is a quadrilateral with their opposite sides are congruent (equal).
The both pairs of opposite sides are given as AB = 3 + x
, DC = 4x
, AD = y + 1
, BC = 2y.
- AB and DC are opposite sides and have same measure of length.
- AD and BC are opposite sides and have same measure of length.
<u>To find the length of AB and DC :</u>
AB = DC
3 + x = 4x
Keep x terms on one side and constant on other side.
3 = 4x - x
3 = 3x
x = 1
Substiute x=1 in AB and DC,
AB = 3+1 = 4
DC = 4(1) = 4
<u>To find the length of AD and BC :</u>
AD = BC
y + 1 = 2y
Keep y terms on one side and constant on other side.
2y-y = 1
y = 1
Substiute y=1 in AD and BC,
AD = 1+1 = 2
BC = 2(1) = 2
Therefore, the opposite sides are of same length AB and DC is 4 and AD and BC is 2. The given quadrilateral ABCD is a parallelogram.
Answer:
1) 4
2) 1.5
3) 8
4) 1
5) 5
6) 9
Step-by-step explanation:
<h3>
1)</h3><h3>
√16</h3>
= √(4x4)
= √(4)²
<h3>= 4</h3>
<h3>
2)</h3><h3>
√2.25</h3>
= √(9/4)
= √(3x3)/(2x2)
= √(3)²/(2)²
= 3/2
<h3>= 1.5</h3>
<h3>3)</h3><h3>6² ÷ 9 x 2 </h3>
= 36 ÷ 9 x 2
= 36 x 1/9 x 2
= 36/9 x 2
= 12/3 x 2
= 4 x 2
<h3>= 8</h3>
<h3>4)</h3><h3>12-2 / 6+4</h3>
= 10/10
<h3>= 1</h3><h3 /><h3>5)</h3><h3>√(16+9)</h3>
= √(25)
= √(5x5)
= √(5)²
<h3>= 5</h3><h3 /><h3>6)</h3><h3>63 ÷ 3² + |2|</h3>
= 63 ÷ 9 + |2|
= 63/9 + |2|
= 21/3 + |2|
= 7 + |2|
<h3>= 9</h3>
