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3 years ago

Pleaseee help me I’m stuck on thisss

Mathematics

1 answer:

Dahasolnce [82]3 years ago

7 0

Answer:

216.90 units

Step-by-step explanation:

Using Pythagoras Theorem:

a² + b² = c²

9² + 10² = 81 + 100 =181 = c²

c = √181 = 13.45

x² + y² = z²

6² + 13.45² = 36 + 180.9025 = 216.9025

= 216.90 units

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3x - 2 = -8 What is x ?

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Answer:

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Step-by-step explanation:

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4 years ago

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Find the sum of – 52 , -36 , 42, 8 ,-22 and 46

vampirchik [111]

-52-36-22+46+42+8 = -18

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3 years ago

Noah’s dog weighs 15 1⁄3 pounds (lbs). Aiden’s dog weighs three times as much as Noah’s. How many pounds does Aiden’s dog weigh?

SpyIntel [72]

<h3>Answer: 46 pounds</h3>

===============================================

Work Shown:

N = weight of Noah's dog = 15 & 1/3 pounds

A = weight of Aiden's dog = unknown

A = 3*N

A = 3*(15 & 1/3)

A = 3*(15 + 1/3)

A = 3*15 + 3*(1/3) .... distribute

A = 45 + 1

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Aiden's dog weighs 46 pounds.

4 0

3 years ago

Which of the following correctly sets up the point-slope equation for this line?

Sophie [7]

Answer: $y + 7 = \frac{1}{3}(x - 6)\\\\$

Work Shown:

$y - y_1 = m(x - x_1)\\\\y - (-7) = \frac{1}{3}(x - 6)\\\\y + 7 = \frac{1}{3}(x - 6)\\\\$

8 0

2 years ago

The American Community Survey showed that residents of New York City have the longest travel times to get to work compared to re

LiRa [457]

Answer:

The probability it will take a resident of the city between 17.24 and 42.13 minutes to travel to work is 0.3046.

Step-by-step explanation:

The random variable X can be defined as the travel times to get to work.

The expected travel time is, μ = 38.3 minutes.

The distribution of random variable X can be defined as the distribution of time interval between which a person reaches their work place at a constant average rate.

This implies that X follows an Exponential distribution with parameter, $\lambda=\frac{1}{\mu}=\frac{1}{38.3}$ .

The probability density function of X is:

$f_{X}(x)=\lambda e^{-\lambda x};\ x\geq 0$

Compute the probability it will take a resident of the city between 17.24 and 42.13 minutes to travel to work as follows:

$P(17.24\leq X\leq 42.13)=\int\limits^{42.13}_{17.24}{\frac{1}{38.3} e^{-x/38.3}}}\, dx$

$=\frac{1}{38.3}\times \int\limits^{42.13}_{17.24}{ e^{-x/38.3}}}\, dx$

$=\frac{1}{38.3}\times| \frac{e^{-x/38.3}}{-1/38.3}}|^{42.13}_{17.24}\\$

$=-e^{42.13/38.3}+e^{17.34/38.3}\\=-0.3329+0.6375\\=0.3046$

Thus, the probability it will take a resident of the city between 17.24 and 42.13 minutes to travel to work is 0.3046.

6 0

3 years ago