Answer:
From what I know there is no q.
p=0 I put a slight explanation below.Hope it helps
Step-by-step explanation:
Ax^2+bx+c-p=x
Ax^2+bx+c-p-x=x-x
Ax^2+(b-1)x+c-p=0
Round two side of measurement and exercise
Slope=
m=(y1-y2)/(x1-x2)
m=(-16--15)/(19--7)
m=(-16+15)/(19+7)
m=(-1)/(26)
Slope is -1/26
When competing the square, you want to have

at the end, and using the fact that the x term and coefficient are really

, we see that the third option is the most efficient way to start
Since y + x = 3, then we could say one of them equals 2 while the other is 1. y - x = 1, then we can say 3 - 1 = 2, so y would be 2 and x would be 1