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NikAS [45]
3 years ago
15

Help 3,00000 x 2,000000 + 2,000000 / 4,000000=?

Mathematics
1 answer:
Rom4ik [11]3 years ago
6 0

Answer:

150000.5

Step-by-step explanation:

300000 x 2000000= 600000000000

600000000000 + 2000000= 600002000000

600002000000/ 4000000= 150000.5

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The figure below shows a quadrilateral ABCD. Sides AB and DC are congruent and parallel:
Stels [109]

Answer:

SAS postulate

Step-by-step explanation:

In the figure attached, quadrilateral ABCD is shown.

The Side Angle Side (SAS) postulate states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent.

AB is congruent to DC, and DB is the side common to triangles ABD and BCD. The included angle between sides AB and DB is angle ABD which is congruent with angle BDC, the angle included between sides DB and DC.

7 0
3 years ago
7,652x5 please regroup I don’t understand :(
scoundrel [369]

Answer:

38260

Step-by-step explanation:

ur welcome

3 0
3 years ago
Read 2 more answers
A<br> Find tan a.<br> r<br> √5,-√7)<br> ✓[?<br> Enter
Virty [35]

Answer:

tan(\alpha)=-\frac{\sqrt{35}}{5}

Step-by-step explanation:

Tan can be defined as: \frac{sin(\theta)}{cos(\theta)} as it simplifies to opposite/adjacent. If you know a bit about the unit circle, you'll know that the x-coordinate is going to be cos(theta) and the y-coordinate is going to be sin(theta). Since the sin(theta) is defined as opposite/hypotenuse, and the hypotenuse = 1, so sin(theta) is defined as the opposite side, which is the y-axis. Same thing goes for cos(theta), except the adjacent side is the x-axis.

Using this we can define tan

sin(\alpha)=-\sqrt{7}\\cos(\alpha)=\sqrt{5}\\\\tan(\alpha)=-\frac{\sqrt{7}}{\sqrt{5}} * \frac{\sqrt{5}}{\sqrt{5}}\\tan(\alpha)=-\frac{\sqrt{7*5}}{5}\\tan(\alpha)=-\frac{\sqrt{35}}{5}\\

8 0
2 years ago
Read 2 more answers
What is the radical form of the expression (2x^4y^5)^3/8
s344n2d4d5 [400]

We are given expression: (2x^4y^5)^{3/8}

Let us distribute 3/8 over exponents in parenthesis, we get

(2^{3/8}x^{4\times 3/8}y^{5\times 3/8}) = (2^{3/8}x^{12/8}y^{15/8})

= (2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} )

We can get x and y out of the radical because, we get whlole number 1 for x and y exponents for the mixed fractions.

So, we could write it as.

(2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} ) = xy(2^{\frac{3}{8} }x^{\frac{4}{8}} y^{\frac{7}{8}} )

Now, we could write inside expression of parenthesis in radical form.

xy\sqrt[8]{2x^{3}x^4y^7}

8 0
3 years ago
Mary scored 28 points, which is twice as many points as Lashawna scored. Let L represent the points Lashawna scored.
Basile [38]

Answer: Lashawna scored 14 points

Step-by-step explanation:

Let M = Mary's score

L = Lashawna score

M = 28 points

And M is twice as much as L score

M= 2L

L= M/2

L= 28/2

M = 14.

Lashawna score was 14 points

8 0
4 years ago
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