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2 years ago

Which will help your answer, "To what power must a student raise the number 5 to have an answer of 626"?

Mathematics

2 answers:

Mazyrski [523]2 years ago

8 0

Answer:

5^x=625

I hope it will be useful.

Snezhnost [94]2 years ago

8 0

Answer:

The Answer us D

Step-by-step explanation:

log5(625)=x

x=4

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I really don’t understand this and just need an explanation of how to do it.

sertanlavr [38]

$\bf ~\hspace{12em}\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\cfrac{2n}{-3n\cdot -2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{-2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n\cdot -n}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n}\cdot \cfrac{1}{-n}$

$\bf \cfrac{1}{-3n}\cdot \boxed{1}\cdot \cfrac{1}{-n}\implies \cfrac{1}{-3n\cdot -n}\implies \cfrac{1}{3n^2}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4\implies \left( \cfrac{1}{3n^2} \right)^4\implies \stackrel{\textit{distributing the exponent}}{\cfrac{1^4}{3^4n^{2\cdot 4}}}\implies \cfrac{1}{81n^8}$

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2 years ago

At an amusement park , the cost of 3 adult tickets and 4 children’s ticket is $126.50 another customer paid $120.50 for 2 adult

KonstantinChe [14]

Answer:

1 Adult ticket=$21.50 ; 1 Children ticket=$15.50

Step-by-step explanation:

3A+4C=126.50

2A+5C=120.50

We find the price of adult tickets 1st.

15A+20C=632.5

8A+20C=482

7A=632.5-482=150.5

1A=21.50

Now we find Children ticket

6A+8C=253

6A+15C=361.50

7C=108.50

1C=15.50

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3 years ago

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kotykmax [81]

Answer:

Step-by-step explanation:

subtract llol

first 1

x . y

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2-4/1-3

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2 years ago

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Kiran has 10 1/2 feet of lumber and wants to make a bookshelfKiran needs two side panels that are each 5 2/3 feet. How much more

eimsori [14]

Total height of lumber, H = 10 1/2 feet = 21/2 feet .

Height of side panel, h = 5 2/3 feet = 17/3 feet .

Now,

Extra lumber required, L = 2 × Height of side panel - Total height of lumber

$L=[2\times (\dfrac{17}{3})]-\dfrac{21}{2}\\\\L = \dfrac{5}{6}\ feet$

Therefore, extra lumber required is $\dfrac{5}{6}$ feet.

Hence, this is the required solution.

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3 years ago

My friend sets out walking at a speed of $3$ miles per hour. I set out behind her $5$ minutes later at $4$ miles per hour. When

r-ruslan [8.4K]

Answer: The answer is 0.25 miles.

Step-by-step explanation: Given that my friend started walking at a speed of 3 miles per hour and I started 5 minutes after him at a speed of 4 miles per hour. We need to find the number of miles my friend travelled when I started walking.

Since I started 5 minutes after than my friend, so we are to find the distance travelled by my friend in 5 minutes.

In 1 hour, i.e., 60 minutes, distance travelled by my friend = 3 miles.

In 1 minute, distance travelled by my friend is

$\dfrac{3}{60}=\dfrac{1}{20}~\textup{miles}.$

Therefore, distance travelled by my friend in 5 minutes will be

$\dfrac{1}{20}\times 5=\dfrac{1}{4}=0.25~\textup{miles}.$

Thus, the answer is 0.25 miles.

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2 years ago

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