HELPP PLEASEE 10 PONITS !! <br><br> Which inequality is represented by this graph?

Ksju [112]

Put the number that the decimal is over the place that it is in
example
.5
every space after the decimal is multiplied by 10
tenths place 0.1
hundreths 0.01
thousanths 0.001
etc
so .5 is in the tenths place so the fraction would be 5/10
the decimal is now converted into a fraction

another example
.07 is in the hundreths so it would be 7/100

final example
.25 is in the hundredths place since the last number lands on the hundreths column
it would be 25/100

if possible you can simplify if that is what is needed

3 0

3 years ago

Researchers are interested in the effect of a certain nutrient on the growth rate of plant seeding. Use a hydroponics grow proce

Rashid [163]

Answer:

The 95% confidence interval for the mean would be given by (56.604;68.596)

The 99% confidence interval for the mean would be given by (53.196;72.004)

Step-by-step explanation:

1) Previous concepts

When we compute a confidence interval for the mean, we are interested on the parameter population mean, and we use the info from the sample to estimate this parameter.

2) Basic operations

The sample mean can be calculated with the following formula

$\sum_{i=1}^n \frac{x_i}{n}$

Using excel we can use this function to calculate the mean:

=AVERAGE(54.2,59.8,61.8,63.3,65.1,71.4)

The value obtained is $\bar X=62.6$

In order to find the sample deviation we can use this formula

$s=\sqrt{\sum_{i=1}^n \frac{(x_i-\bar X)^2}{n-1}}$

And using excel we can use this function to calculate the sample standard deviation:

=STDEV.S(54.2,59.8,61.8,63.3,65.1,71.4)

The value obtained is $s=5.713$

The sample size for this case is n=6, n<30 so then is better use the t distribution to calculate the margin of error. First we need to calculate the degrees of freedom, on this case $df=n-1=6-1=5$

The formula for the confidence interval would be given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

3) Part a

If we want a 95% or 0.95 of confidence, then the value for the signficance is $\alpha=1-0.95=0.05$ , and $\alpha/2=0.025$ , and $1-\frac{\alpha}{2}=0.975$ so we can find the critical t value with the following formula in excel:

=T.INV(0.975,5)

And we got $t_{\alpha/2}= 2.571$

And we can replace into equation (1) and we got:

$62.6 \pm 2.571\frac{5.713}{\sqrt{6}}$

And using excel with the following formulas we got:

=62.6-2.571*(5.713/SQRT(6)) = 56.604

=62.6+2.571*(5.713/SQRT(6)) = 68.596

So the 95% confidence interval for the mean would be given by (56.604;68.596)

4) Part b

If we want a 99% or 0.99 of confidence, then the value for the signficance is $\alpha=1-0.99=0.01$ , and $\alpha/2=0.005$ , and $1-\frac{\alpha}{2}=0.995$ so we can find the critical t value with the following formula in excel:

=T.INV(0.995,5)

And we got $t_{\alpha/2}= 4.032$

And we can replace into equation (1) and we got:

$62.6 \pm 4.032\frac{5.713}{\sqrt{6}}$

And using excel with the following formulas we got:

=62.6-4.032*(5.713/SQRT(6)) = 53.196

=62.6+4.032*(5.713/SQRT(6)) = 72.004

So the 99% confidence interval for the mean would be given by (53.196;72.004)

8 0

3 years ago

Now convert 3/8 to a decimal number by completing the long division. Remember to add 0s to the dividend as you work. Divide thro

VMariaS [17]

Answer:

you feel happy with the process on the long division page you can skip the first bit.

divide step 1 4 ÷ 25 = 0 remainder 4 The first number of the dividend is divided by the divisor.

divide step 2 The whole number result is placed at the top. Any remainders are ignored at this point.

divide step 3 25 × 0 = 0 The answer from the first operation is multiplied by the divisor. The result is placed under the number divided into.

divide step 4 4 − 0 = 4 Now we take away the bottom number from the top number.

divide step 5 Bring down the next number of the dividend.

divide step 6 43 ÷ 25 = 1 remainder 18 Divide this number by the divisor.

divide step 7 The whole number result is placed at the top. Any remainders are ignored at this point.

divide step 8 25 × 1 = 25 The answer from the above operation is multiplied by the divisor. The result is placed under the last number divided into.

divide step 9 43 − 25 = 18 Now we take away the bottom number from the top number.

divide step 10 Bring down the next number of the dividend.

divide step 11 185 ÷ 25 = 7 remainder 10 Divide this number by the divisor.

divide step 12 The whole number result is placed at the top. Any remainders are ignored at this point.

divide step 13 25 × 7 = 175 The answer from the above operation is multiplied by the divisor. The result is placed under the number divided into.

divide step 14 185 − 175 = 10 Now we take away the bottom number from the top number.

divide step 15 Now we have reached the end of the whole numbers we add a decimal place and the first zero. Notice the decimal point which has appeared on the answer line and by the dividend. It does not appear anywhere else.

divide step 16 Bring down the next number of the dividend.

divide step 17 100 ÷ 25 = 4 remainder 0 Divide this number by the divisor.

divide step 18 The whole number result is placed at the top. Any remainders are ignored at this point.

divide step 19 25 × 4 = 100 The answer from the above operation is multiplied by the divisor. The result is placed under the number divided into.

divide step 20 100 − 100 = 0 Now we take away the bottom number from the top number.

divide step 21

The subtraction has given zero. We stop when this happens. The answer is 17.4

As long as the subtraction gives a number above zero the long division can carry on to as many decimal places as we wish.

Answer: 435 ÷ 25 = 17.4 FOLLOW ME

6 0

3 years ago

Helppppppppp pleassseee

prisoha [69]

Answer:

D.) SSS

Step-by-step explanation:

Considering the proof tells us that many sides seem congruent to each other, I am led to believe these triangles are congruent due to SSS.

8 0

3 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

NeX [460]

Answer:

(a) 0.343

(b) 0.657

(c) 0.189

(d) 0.216

(e) 0.353

Step-by-step explanation:

Let P(a vehicle passing the test) = p

$p = \frac{70}{100} = 0.7$

Let P(a vehicle not passing the test) = q

q = 1 - p

q = 1 - 0.7 = 0.3

(a) P(all of the next three vehicles inspected pass) = P(ppp)

= 0.7 × 0.7 × 0.7

= 0.343

(b) P(at least one of the next three inspected fails) = P(qpp or qqp or pqp or pqq or ppq or qpq or qqq)

= (0.3 × 0.7 × 0.7) + (0.3 × 0.3 × 0.7) + (0.7 × 0.3 × 0.7) + (0.7 × 0.3 × 0.3) + (0.7 × 0.7 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.3)

= 0.147 + 0.063 + 0.147 + 0.063 + 0.147 + 0.063 + 0.027

= 0.657

(c) P(exactly one of the next three inspected passes) = P(pqq or qpq or qqp)

= (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.063 + 0.063 + 0.063

= 0.189

(d) P(at most one of the next three vehicles inspected passes) = P(pqq or qpq or qqp or qqq)

= (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7) + (0.3 × 0.3 × 0.3)

= 0.063 + 0.063 + 0.063 + 0.027

= 0.216

(e) Given that at least one of the next 3 vehicles passes inspection, what is the probability that all 3 pass (a conditional probability)?

P(at least one of the next three vehicles inspected passes) = P(ppp or ppq or pqp or qpp or pqq or qpq or qqp)

= (0.7 × 0.7 × 0.7) + (0.7 × 0.7 × 0.3) + (0.7 × 0.3 × 0.7) + (0.3 × 0.7 × 0.7) + (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.343 + 0.147 + 0.147 + 0.147 + 0.063 + 0.063 + 0.063

= 0.973

With the condition that at least one of the next 3 vehicles passes inspection, the probability that all 3 pass is,

$= \frac{P(all\ of\ the\ next\ three\ vehicles\ inspected\ pass)}{P(at\ least\ one\ of\ the\ next\ three\ vehicles\ inspected\ passes)}$

$= \frac{0.343}{0.973}$

= 0.353

3 0

3 years ago

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HELPP PLEASEE 10 PONITS !! Which inequality is represented by this graph?