2 years ago

what is the center and radius of the circle given the equation, 8x + x-squared - 2y + y-squared - 64 = 0?

Mathematics

1 answer:

RoseWind [281]2 years ago

7 0

Step-by-step explanation:

8x + x² - 2y + y² - 64 = 0

(x + 4)² + (y - 1)² - 81 = 0

(x + 4)² + (y - 1)² = 81

Hencr the center is (-4,1) and the radius is 9.

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Which is the graph of the cube root function f(x) = RootIndex 3 StartRoot x EndRoot?

lara [203]

Answer:

<h3>On a coordinate plane, a cube root function goes through (negative 8, negative 2), has an inflection point at (0, 0), and goes thorugh (8, 2).</h3>

Step-by-step explanation:

$f(x)=\sqrt[3]{x}\\\\f(-8)=\sqrt[3]{-8}=-2\to(-8,\ -2)\\\\f(0)=\sqrt[3]{0}=0\to(0,\ 0)\\\\f(8)=\sqrt[3]{8}=2\to(8,\ 2)\\\\\\\sqrt[3]{a}=b\iff b^3=a\\\\\text{Therefore:}\\\\\sqrt[3]{-8}=-2\ \text{because}\ (-2)^3=-8\\\sqrt[3]0=0\ \text{because}\ 0^3=0\\\sqrt[3]{8}=2\ \text{because}\ 2^3=8$