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3 years ago

what is the center and radius of the circle given the equation, 8x + x-squared - 2y + y-squared - 64 = 0?

Mathematics

1 answer:

RoseWind [281]3 years ago

7 0

Step-by-step explanation:

8x + x² - 2y + y² - 64 = 0

(x + 4)² + (y - 1)² - 81 = 0

(x + 4)² + (y - 1)² = 81

Hencr the center is (-4,1) and the radius is 9.

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Write the next 4 terms of the sequence -4, -1, 4, 11

garri49 [273]

Answer:

20, 31, 44, 59

Step-by-step explanation:

find difference between

-4 and -1 is 3

-1 and 4 is 5

4 and 11 is 7

next term: 11+9=20

next term: 20+11=31

next term: 31+13=44

next term: 44+15=59

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3 years ago

Given ABC, use a dilation with the center at the

oee [108]

Answer: (6,-3)

Trust me, I just checked the answer.

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3 years ago

Ellie uses a 2.50 pounds of potatoes to make mashed potatoes she uses a 110 that as many pounds of butter as a potatoes how many

Paul [167]

Ellie uses 275 pounds of butter. This is because they key words are 'as many pounds of butter as potatoes' this means to multiply so 2.50 x 110 equals 275.

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3 years ago

What are the coordinates of point S"? (negative three-halves, nine-halves) (negative nine-halves, fifteen-halves) (nine-halves,

kow [346]

Answer:

$S=(\frac{9}{2},-\frac{3}{2})$

Step-by-step explanation:

The missing details are:

$T= (0,4)$

$M = (\frac{9}{4}, \frac{5}{4})$ --- Midpoint of ST

Required

Determine the coordinates of S

To do this, we apply the mid-point formula:

$M(x,y) = \frac{1}{2}(x_1+x_2,y_1+y_2)$

Where

$M(x,y) = (\frac{9}{4}, \frac{5}{4})$

$T(x_1,y_1) - (0,4)$

The equation becomes:

$M(x,y) = \frac{1}{2}(x_1+x_2,y_1+y_2)$

$(\frac{9}{4},\frac{5}{4}) = \frac{1}{2}(0+x_2,4+y_2)$

$(\frac{9}{4},\frac{5}{4}) = \frac{1}{2}(x_2,4+y_2)$

Multiply through by 2

$2*(\frac{9}{4},\frac{5}{4}) = 2*\frac{1}{2}(x_2,4+y_2)$

$(\frac{9}{2},\frac{5}{2}) = (x_2,4+y_2)$

By comparison:

$x_2 = \frac{9}{2}$

$4 + y_2 =\frac{5}{2}$

$y_2 =\frac{5}{2}-4$

$y_2 =\frac{5-8}{2}$

$y_2 =-\frac{3}{2}$

Hence, the coordinates of S is:

$S=(\frac{9}{2},-\frac{3}{2})$

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3 years ago

The freezing point of of gasoline is about -50 degrees Celsius, and the freezing point of water is 0 degrees Celsius. What is th

LenaWriter [7]

Answer:

the difference is that -50 is -50 celsius from 0 hope this helps at all!?

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers