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2 years ago

nervous laugh SO ummm geometry isnt my thing actually im rather bad it please help!

Mathematics

2 answers:

Savatey [412]2 years ago

8 0

I believe the answer would be D 92 and 88 hope it helped

gregori [183]2 years ago

6 0

Te answer is C 100 and 80 straight lines equal out to be 180*

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How do you solve this problem: 5(x3)-(-20)

Nimfa-mama [501]

First step: multiply the 5(x3) and it will give you x15 or most commonly written as 15x. you should now have 15x-(-20).

Second step: since you cannot subtract -20 from 15x because it has a variable, the final answer is just 15x-(-20), or 15x+20.

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2 years ago

Distributive property 7x110

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A right triangle has a hypotenuse of 43 cm and an angle of 56° opposite leg m. What is the length of leg m rounded to the neares

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Step-by-step explanation:

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2 years ago

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Describes the function y = -2 x + 5?

nevsk [136]

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I don't know if this is what you meant, but it's a linear equation.

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3 years ago

Solve the following initial-value problem, showing all work, including a clear general solution as well as the particular soluti

Vikki [24]

Answer:

General Solution is $y=x^{3}+cx^{2}$ and the particular solution is $y=x^{3}-\frac{1}{2}x^{2}$

Step-by-step explanation:

$x\frac{\mathrm{dy} }{\mathrm{d} x}=x^{3}+3y\\\\Rearranging \\\\x\frac{\mathrm{dy} }{\mathrm{d} x}-3y=x^{3}\\\\\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{3y}{x}=x^{2}$

This is a linear diffrential equation of type

$\frac{\mathrm{d} y}{\mathrm{d} x}+p(x)y=q(x)$ ..................(i)

here $p(x)=\frac{-2}{x}$

$q(x)=x^{2}$

The solution of equation i is given by

$y\times e^{\int p(x)dx}=\int e^{\int p(x)dx}\times q(x)dx$

we have $e^{\int p(x)dx}=e^{\int \frac{-2}{x}dx}\\\\e^{\int \frac{-2}{x}dx}=e^{-2ln(x)}\\\\=e^{ln(x^{-2})}\\\\=\frac{1}{x^{2} } \\\\\because e^{ln(f(x))}=f(x)]\\\\Thus\\\\e^{\int p(x)dx}=\frac{1}{x^{2}}$

Thus the solution becomes

$\tfrac{y}{x^{2}}=\int \frac{1}{x^{2}}\times x^{2}dx\\\\\tfrac{y}{x^{2}}=\int 1dx\\\\\tfrac{y}{x^{2}}=x+c$ $y=x^{3}+cx^{2$

This is the general solution now to find the particular solution we put value of x=2 for which y=6

we have $6=8+4c$

Thus solving for c we get c = -1/2

Thus particular solution becomes

$y=x^{3}-\frac{1}{2}x^{2}$

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3 years ago

*nervous laugh* SO ummm geometry isnt my thing actually im rather bad it please help!

nervous laugh SO ummm geometry isnt my thing actually im rather bad it please help!