Question

PLEASE HELP ME IM STUCKKKKK

Answer 1

Answer:

$x=\sqrt{10}$

Step-by-step explanation:

For first right angled tringle,

Hypotenuse = 10

Height = 9

We can find the base of first triangle using Pythagoras therorem,

$b=\sqrt{10^2-9^2}\\\\=\sqrt{100-81}\\\\=\sqrt{19}$

Now, for other triangle,

Height = 3

Hypotenuse = $\sqrt{19}$

So,

$x=\sqrt{(\sqrt{19})^2-3^2}\\\\=\sqrt{19-9}\\\\=\sqrt{10}$

So, the value of x is equal to $\sqrt{10}$.