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Mariulka [41]
3 years ago
8

Sandeep used 8 litres of fuel to travel 76 miles.

Mathematics
1 answer:
OleMash [197]3 years ago
4 0

Answer:

I got, when calculated, 209 miles. (It may be wrong)

Step-by-step explanation:

First, I calculated how many miles can Sandeep travel with 1L, therefore I divided 76 miles by 8L and got 9.5 miles on 1L.

Then I multiplied 9.2 miles by 22L and got 209 miles.

This may be wrong but if anyone else is able to work it out much appreciated if it's correct.. Your most welcome!

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This diagram shows a block of stainless steel. The mass of the block is 930g.
EastWind [94]

Answer:7.75

Step-by-step explanation:

3 0
3 years ago
identify the type of conic section that has the equation 4x^2+25y^2=100 and identify its domain and range.
Vika [28.1K]

4x^2+25y^2=100

4x^2+25y^2=100 \\\\
Dividing \;both \;sides \;by \;100 \\\\
\frac{4x^2}{100}+ \frac{25y^2}{100}= \frac{100}{100} \\\\
\frac{x^2}{25}+ \frac{y^2}{4}= 1 \\\\
\frac{x^2}{5^2}+ \frac{y^2}{2^2}= 1 \\\\
This \;is \;an \;ellipse. \\\\ \frac{x^2}{a^2}+ \frac{y^2}{b^2}= 1

Domain of an ellipse is x ∈ [-a,a] and Range of an ellipse is y ∈ [-b,b].

So, given equation is an Ellipse where Domain is x ∈ [-5,5] and Range is y ∈ [-2,2].

4 0
3 years ago
X to the 3rd power= 64/343
leva [86]

Answer:

x = 4/7

Step-by-step explanation:

x^3 = 64/ 343 // - 64/ 343

x^3 - ( 64/ 343 ) = 0

x^3 - 64 / 343 = 0

1*x^3 = 64/ 343 // : 1

x^3 = 64/ 343

x^3 = 64/ 343 // ^ 1/3

x = 4/ 7

5 0
3 years ago
Find the midsegment of the triangle which is parallel to CA.​
Nataliya [291]

Answer:

\pmb{ \pink{QUESTION�}}

Find the midsegment of the triangle which is parallel to CA.

\pmb{ \pink{ANSWER:-}}

Tip

  • A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
  • This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
  • If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.

\frak{Explanation:-}

We have to find the segment which is parallel to CA.

From the given data,

The segment EG is the midsegment of the triangle\triangle ABC.

So we have,

A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.

\implies\rm{midsegment \:  EG \: parallel \: to \:  CA}

\frak{RainbowSalt}~

6 0
2 years ago
Read 2 more answers
Barry read for 15 more minutes than Robert.
Greeley [361]
Hi!

C. v + 15

Barry read for 15 MORE minutes than Robert.
6 0
3 years ago
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