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Hoochie [10]
3 years ago
14

A scale factor of 1/6 was used to create the scale drawing of a rectangular garden. The length of the garden on the map is 3 inc

hes. What is the length of the actual garden in feet?
Can anyone explain how to do this?
Mathematics
1 answer:
frozen [14]3 years ago
7 0

Answer:

The length of the garden in feet would be 0.25ft

Step-by-step explanation:

3 is 1/4 25% of 12 (foot)

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38.91 what is the value of 8
Amanda [17]
8 is in the ones place so 8 ones.
6 0
3 years ago
An 8 kg box is at rest and is pushed for 10 m with a 60 N force. If it's accelerated to 10 m/s, calculate the efficiency of the
wlad13 [49]

Answer:

  2/3

Step-by-step explanation:

The work done on the box is ...

  Fd = (60 N)(10 m) = 600 N·m = 600 J

The amount of energy the box has as a result is ...

  KE = 1/2mv² = (1/2)(8 kg)(10 m/s)² = 400 kg·m²/s² = 400 J

The ratio of box energy to energy input is ...

  η = (400 J)/(600 J) = 2/3 . . . ≈ 66.7%

4 0
3 years ago
To display The number of female members in band class over the past five years use a
Alina [70]

Answer:

For the 1st row its Line Graph and Changes over time.

For the 2nd Row its Bar Graph and Categorical.

Step-by-step explanation:

7 0
3 years ago
Parker throws a ball off the top of a building. The building is 350 feet high and the initial velocity of the ball is 30 feet pe
viva [34]

Answer:

5.707

Step-by-step explanation:

5 0
4 years ago
Evaluate using the finite geometric sum formula
Sever21 [200]

Answer:

S_9=-18.703.

Step-by-step explanation:

The given series is,

\sum_{i=1}^9(-\frac{1}{2})^{i-1}

When we substitute i=1, we get the first term, which is a_1=-28(-\frac{1}{2})^{1-1}


This implies that,

a_1=-28(-\frac{1}{2})^{0}


a_1=-28(1)=-28.


The common ratio is

r=-\frac{1}{2}


The finite geometric sum is given by the formula,

S_n=\frac{a_1(r^n-1)}{r-1} , -1\:.


Since there are 9 terms, we find the sum of the first nine terms by putting n=9 in to the formula to get,


S_9=\frac{-28((-\frac{1}{2})^9-1)}{-\frac{1}{2}-1}.


S_9=\frac{-28((-\frac{1}{2})^9-1)}{-\frac{1}{2}-1}.


S_9=\frac{-28((-\frac{1}{512})-1)}{-\frac{3}{2}}.


S_9=\frac{-28(-\frac{513}{512})}{-\frac{3}{2}}.


S_9=-28(\frac{171}{256}).


S_9=-\frac{1197}{64}.



S_9=-18.703.


The correct answer is B





4 0
3 years ago
Read 2 more answers
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