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Gelneren [198K]
3 years ago
7

38.91 what is the value of 8

Mathematics
1 answer:
Amanda [17]3 years ago
6 0
8 is in the ones place so 8 ones.
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Suppose approximately 75% of all marketing personnel are extroverts, whereas about 70% of all computer programmers are introvert
Setler [38]

Answer:

P(x \ge 5) = 1.000 ---- At least 5 from marketing departments are extroverts

P(x=15) = 0.013 ---- All from marketing departments are extroverts

P(x = 0) = 0.002 ---------- None from computer programmers are introverts

Step-by-step explanation:

See comment for complete question

The question is an illustration of binomial probability where

P(x) = ^nC_x * p^x * (1 - p)^{n-x}

(a):\ P(x \ge 5)

n = 15 --- marketing personnel

p = 75\% --- proportion that are extroverts

Using the complement rule, we have:

P(x \ge 5) = 1 - P(x < 5)

So, we have:

P(x < 5) =P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)

P(x = 0) = ^{15}C_{0} * (75\%)^0 * (1 - 75\%)^{15 - 0} = 1 * 1 * (0.25)^{15} = 9.31 * 10^{-10}

P(x = 1) = ^{15}C_{1} * (75\%)^1 * (1 - 75\%)^{15 - 1} = 15* (0.75)^1 * (0.25)^{14} = 4.19 * 10^{-8}

P(x = 2) = ^{15}C_{2} * (75\%)^2 * (1 - 75\%)^{15 - 2} = 105* (0.75)^2 * (0.25)^{13} = 8.80 * 10^{-7}

P(x = 3) = ^{15}C_{3} * (75\%)^3 * (1 - 75\%)^{15 - 3} = 455* (0.75)^2 * (0.25)^{12} = 0.0000153

P(x = 4) = ^{15}C_{4} * (75\%)^4 * (1 - 75\%)^{15 - 4} = 1365 * (0.75)^4 * (0.25)^{11} = 0.000103

So, we have:

P(x < 5) = (9.31 * 10^{-10}) + (4.19 * 10^{-8}) + (8.80 * 10^{-7}) + 0.0000153 + 0.000103

P(x < 5) = 0.00011922283

Recall that:

P(x \ge 5) = 1 - P(x < 5)

P(x \ge 5) = 1 - 0.00011922283

P(x \ge 5) = 0.9998

P(x \ge 5) = 1.000 --- approximated

(b)\ P(x = 15)

n = 15 --- marketing personnel

p = 75\% --- proportion that are extroverts

So, we have:

P(x) = ^nC_x * p^x * (1 - p)^{n-x}

P(x=15) = ^{15}C_{15} * 0.75^{15} * (1 - 0.75)^{15-15}

P(x=15) = 1 * 0.75^{15} * (0.25)^{0

P(x=15) = 0.013

(c)\ P(x = 0)

n=5 ---------- computer programmers

p = 70\% --- proportion that are introverts

So, we have:

P(x) = ^nC_x * p^x * (1 - p)^{n-x}

P(x = 0) = ^{5}C_0 * (70\%)^0 * (1 - 70\%)^{5-0}

P(x = 0) = 1 * 1 * (0.30)^5

P(x = 0) = 0.002

3 0
2 years ago
Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an
marishachu [46]

Answer: x+x^2+x^3+x^4

Step-by-step explanation:

As per given,

Number of wives = x

Number of sacks = x (\text{Number of wives} )= x\times x = x^2

Number of cats = x(\text{Number of sack})= x \times x^2=x^3

Number of kits = x(\text{Number of cats} )=x\times x^3=x^4

Now , the total number of kits, cats, sacks, and wives going to St. Ives = x+x^2+x^3+x^4

Hence, the required ex[pression:  x+x^2+x^3+x^4

5 0
3 years ago
Can you help me with this question please
solniwko [45]

Answer:

the answer is 9^8

Step-by-step explanation:

9^3 * 9^5 = 9^ 3 + 5 = 9^8

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bp%7D%7B%20-%208%7D%20%20%2B%209%20%3E%2013" id="TexFormula1" title=" \frac{p}{ -
Gnom [1K]

is the answer open circle?

7 0
3 years ago
Read 2 more answers
Wqolsak,fdsf nlkdsflksfksdjfkdsfjslkdafj
jarptica [38.1K]

Answer:

ksnbdndk djdbnsjsksk djdjjsksks ksksj dndjjdjsjsjkskdkd

4 0
3 years ago
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