Determine the equation of the line perpendicular to the line 4x+2y-7=0 that has the same x-intercept as the line 2x+3y-12=0
1 answer:
Let’s first make a blank equation in slope-intercept form: y=mx+b
To find the slope, we find the perpendicular slope to 4x+2y-7=0. First, change this to slope-intercept form:
4x+2y=7
2y=7-4x
y=-2x+(7/2)
The slope of this line is -2, so the perpendicular slope will be the opposite inverse, or 1/2. This is the first component.
Second, to find the x-intercept of 2x+3y-12=0, we have to set y=0 and solve:
2x+3(0)=12
2x=12
x=6 or (6,0)
So in total, we need a line with a slope of 1/2 passing through (6,0). Plug this back into y=mx+b:
0=1/2(6)+b
0=3+b
b=-3
So in total, the equation is y=(1/2)x-3.
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2x−3y+8=0
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That's how I knew it
hopes it helps you
And
your welcomeee
<<<::
Answer:
what are you asking exactly?
Answer:
47/100
Step-by-step explanation:
First you have to make the denominators equal.
4/10 * 10/10 = 40/100
40/100 + 7/100 = 47/100