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Yakvenalex [24]
3 years ago
9

Two gym classes are participating in Field Day. One class has 24 students and the other has 27 students. The gym teachers want t

o divide the students in each class into the largest possible equal groups, with no students left over. If all the groups have the same number of students, how many students are in each group?
HELP
Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
7 0

Answer:

Step-by-step explanation:

Class 1: 24 students

Class 2: 27 students

24+27=51

51 divided by 2 = 25.5

25.5 students are in each group

Masteriza [31]3 years ago
3 0

Answer:

one class 25 and the other 26

Step-by-step explanation:

That's because if there is 24 students in each class then 3 students will be left in which the other class will take two and the other 1 student

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Land's Bend sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the intern
Naya [18.7K]

Answer:

80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases (\mu_1-\mu_2) is [-9.132 , 23.332].

Step-by-step explanation:

We are given that a random sample of 7 sales receipts for mail-order sales results in a mean sale amount of $81.70 with a standard deviation of $18.75.

A random sample of 11 sales receipts for internet sales results in a mean sale amount of $74.60 with a standard deviation of $28.25.

Firstly, the Pivotal quantity for 80% confidence interval for the difference between population means is given by;

                            P.Q. =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }  ~ t__n__1-_n__2-2

where, \bar X_1 = sample mean sales receipts for mail-order sales = $81.70

\bar X_2 = sample mean sales receipts for internet sales = $74.60

s_1 = sample standard deviation for mail-order sales = $18.75

s_2 = sample standard deviation for internet sales = $28.25

n_1 = size of sales receipts for mail-order sales = 7

n_2 = size of sales receipts for internet sales = 11

Also, s_p=\sqrt{\frac{(n_1-1)s_1^{2} +(n_2-1)s_2^{2} }{n_1+n_2-2} } = \sqrt{\frac{(7-1)\times 18.75^{2} +(11-1)\times 28.25^{2} }{7+11-2} } = 25.11

<em>Here for constructing 80% confidence interval we have used Two-sample t test statistics as we don't know about population standard deviations.</em>

<em />

So, 80% confidence interval for the difference between population means, (\mu_1-\mu_2) is ;

P(-1.337 < t_1_6 < 1.337) = 0.80  {As the critical value of t at 16 degree

                                         of freedom are -1.337 & 1.337 with P = 10%}  

P(-1.337 < \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } < 1.337) = 0.80

P( -1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } < {(\bar X_1-\bar X_2)-(\mu_1-\mu_2)} < 1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ) = 0.80

P( (\bar X_1-\bar X_2)-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } < (\mu_1-\mu_2) < (\bar X_1-\bar X_2)+1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ) = 0.80

<u>80% confidence interval for</u> (\mu_1-\mu_2) =

[ (\bar X_1-\bar X_2)-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } , (\bar X_1-\bar X_2)+1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ]

= [ (81.70-74.60)-1.337 \times {25.11 \times \sqrt{\frac{1}{7} +\frac{1}{11} } } , (81.70-74.60)+1.337 \times {25.11 \times \sqrt{\frac{1}{7} +\frac{1}{11} } } ]

= [-9.132 , 23.332]

Therefore, 80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases (\mu_1-\mu_2) is [-9.132 , 23.332].

4 0
3 years ago
Your mom asked you to turn the oven down to 325 degrees Fahrenheit. This is 75 degrees Fahrenheit than it was. What was the orig
Flauer [41]
I think you add 325 and 75 = 400
400 is the original temperature

Hopefully this helps...
4 0
3 years ago
-20 ? I’m a little confused on the “2x” part
Brut [27]

whatever you do to one side, you must do to the other side to keep the equation balanced.

in order to isolate the variable (x), you need to divide by 2.  Since you are dividing the right side by 2, then you must divide the left side by 2.

-10÷2  = 2÷2x

-5  = 1x

-5 = x

3 0
3 years ago
Graph the equation y = 3x - 6<br> Select two points to graph the line.
LiRa [457]

Answer:

y intercept is -6 put your first point on that y intercept

Step-by-step explanation:

from -6  rise 3 and run 1 (to the right )

whats that point ?  (0,2)

from  that point 2.... run 1 ( to the right and up 3) that will take from x4 to y6

(0,2) (4,6) Two points

y2 -y1 = 6

x2-x1  =2

6/2 simplified is 3/1

Make sense?

4 0
3 years ago
34 + 3 ⋅ 5 = ____. (Input whole numbers only.) Numerical Answers Expected!
vladimir2022 [97]

[ Answer ]

\boxed{49}

[ Explanation ]

34 + 3 · 5 = _____

Parenthesis

Exponents

Multiply

Divide

Add

Subtract

Multiply

3 * 5 = 15

Add

34 + 15

Final Answer

49

\boxed{[ \ Eclipsed \ ]}

7 0
3 years ago
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