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victus00 [196]
2 years ago
12

Big Nicks moving company unloaded 72 % of the 300 boxes they delivered in 30 minutes. How many boxes did they unload each minute

?
Mathematics
1 answer:
jeka57 [31]2 years ago
4 0
72 % of 300 is 216

Divide 216 ( # of boxes unloaded ) by 30 (minutes they were unloading)
216 / 30 = 7.2

They unloaded 7.2 boxes each minute.

**DOUBLE CHECK:
Multiply 7.2 by 30
7.2*30 = 216

Answer : 7.2 boxes/minute
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shtirl [24]
Isn’t it?
Trying K.
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5 0
3 years ago
The number of men and women participating in the Winter Olympic Games has been steadily increasing in recent years. In the 19th
Montano1993 [528]

Using a system of equations, it is found that the correct option is:

A) 1389x+1660y=787x+1121y.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, considering the amounts in each olympics(1389 men and 787 women participated on the 19th, 1660 men and 1121 women in the 22th), the system is:

A) 1389x+1660y=787x+1121y.

More can be learned about a system of equations at brainly.com/question/24342899

6 0
2 years ago
Hey friend please solve this question
Bas_tet [7]

yes and yes.

you're told ∠A=∠B. this means angle A and B are equal. so the value you get for cos A will be the same as the value you'll get for cos B

also, the value you get for tan A will be the same as the value you'll get for tan B


if that doesn't make sense you could also draw the triangle and solve for A and B.

you're told it's a right angled triangle meaning one of the angles = 90

you're told that C is that angle so if C is a right angle, angle C=90

the sum of all the angles in a triangle = 180

so angle A+ angle B + angle C = 180

angle A+ angle B + 90 = 180

angle A+ angle B = 180 - 90

angle A+ angle B = 90

  • A and B could be any value but you're told angle A = angle B

        angle A+ angle B = 90

        you can divide 90 by 2 because A and B are equal. that will give you 45 for A and 45 for B

or

  • angle A+ angle B = 90

        since angle A = angle B,

1. you can substitute angle A with angle B like this

  angle B+ angle B = 90

  2 angle B = 90

  angle B = 90/2

  angle B=45; ∴ angle A is also 45 ( because angle A= angle B)

2. or you could substitute angle B with angle A

   angle A+ angle A = 90

2 angle A = 90

  angle A = 90/2

  angle A =45; ∴ angle B is also 45 ( because angle A= angle B)


Now you know what A and B are,

sin A = sin 45; sin B = sin 45

sin 45 = sin 45

tan A = tan 45; tan B = tan 45

tan 45 = tan 45

7 0
3 years ago
If andre collects $9.80, how many cups did he sell?
barxatty [35]

Answer:

we need more information

5 0
2 years ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
Tomtit [17]

Apparently my answer was unclear the first time?

The flux of <em>F</em> across <em>S</em> is given by the surface integral,

\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S

Parameterize <em>S</em> by the vector-valued function <em>r</em>(<em>u</em>, <em>v</em>) defined by

\mathbf r(u,v)=7\cos u\sin v\,\mathbf i+7\sin u\sin v\,\mathbf j+7\cos v\,\mathbf k

with 0 ≤ <em>u</em> ≤ π/2 and 0 ≤ <em>v</em> ≤ π/2. Then the surface element is

d<em>S</em> = <em>n</em> • d<em>S</em>

where <em>n</em> is the normal vector to the surface. Take it to be

\mathbf n=\dfrac{\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}}{\left\|\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}\right\|}

The surface element reduces to

\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\mathbf n\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv

\implies\mathbf n\,\mathrm dS=-49(\cos u\sin^2v\,\mathbf i+\sin u\sin^2v\,\mathbf j+\cos v\sin v\,\mathbf k)\,\mathrm du\,\mathrm dv

so that it points toward the origin at any point on <em>S</em>.

Then the integral with respect to <em>u</em> and <em>v</em> is

\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S=\int_0^{\pi/2}\int_0^{\pi/2}\mathbf F(x(u,v),y(u,v),z(u,v))\cdot\mathbf n\,\mathrm dS

=\displaystyle-49\int_0^{\pi/2}\int_0^{\pi/2}(7\cos u\sin v\,\mathbf i-7\cos v\,\mathbf j+7\sin u\sin v\,\mathbf )\cdot\mathbf n\,\mathrm dS

=-343\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}\cos^2u\sin^3v\,\mathrm du\,\mathrm dv=\boxed{-\frac{343\pi}6}

4 0
3 years ago
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