Question

1. A manager uses the following equation to predict monthly receipts: Y=450+10t time in weeks and y = receipts.) What is the forecast for July 14th if t=4 is the fourth week in January and t = 6 is February 14th of the same year (assume there are 4 weeks in each month)?
a. 690
b. 710
c. 730
d. 750
2. A major reason that decision making is often not such a rational process is that there are: Suppose we have H0:µ1= µ2 versus HA: µ1 ≠ µ2, with level of significance of α =.05 and critical values of zα/2 = ± 1.96, and the computed Test Statistics value of Z = -1.07. What is our decision?

Answer 1

Answer:

1. 690

2. Do not reject the null hypothesis.

Explanation:

1. Month       t

At the end of Feb    6

March                       4

April                          4

May                           4

June                          2

14th of July               2

Total                         24

Therefore on 14th July, t = 24

Forecast: Y = 450+10t = 450 + 10*24 = 450+240 = 690

2. Options are "a. Reject the null hypothesis. b. Do not reject the null hypothesis. c. Take a larger sample. d. Reserve judgment"

In general, if test statistic is more extreme than the critical values at given level of significance then we reject the null hypothesis otherwise we do not reject the null hypothesis.

Here, test statistic for the given two tailed test is Z = -1.07 and critical value at level of significance α = 0.5 is ± 1.96 . Since -1.96<Z<1.96, we can say that we do not reject Null Hypothesis as the test statistic is not extreme than the critical value at given level of significance.