Henri Henri use his GPS to measure the distance from his house to two locations to the thousands of miles then he rounded both values to the nearest hundred which pair of distances could be the nearest actual distances please mark me as brainless I’m really helpful and I did this the answer is 4.32
Answer:
≈ 7.6
Step-by-step explanation:
Calculate the distance using the distance formula
d = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (- 1, - 1) and (x₂, y₂ ) = (6, 2)
d = 
= 
= 
=
≈ 7.6 ( to the nearest tenth )
Answer:
80,00
Step-by-step explanation:
According to my research, the formula for the Area of a rectangle is the following,

Where
- A is the Area
- L is the length
- W is the width
Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>
800 / 2 = 400ft
So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.
400/2 = 200 ft
Now we can calculate the maximum Area using the values above.


So the Maximum area we are able to create with 800 ft of fencing is 80,00
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this is the one that I did
Answer:
m∠Q = 121°
m∠R = 58°
m∠S = 123°
m∠T = 58°
Step-by-step explanation:
The sum of the interior angles of a quadrilateral = 360°
Create an expression for the sum of all the angles and equate it to 360, then solve for x:
∠Q + ∠T + ∠S + ∠R = 360
⇒ 2x + 5 + x + 2x + 7 + x = 360
⇒ 6x + 12 = 360
⇒ 6x = 360 - 12 = 348
⇒ x = 348 ÷ 6 = 58
So now we know that x = 58, we can calculate all the angles:
m∠Q = 2x + 5 = (2 x 58) + 5 = 121°
m∠R = x = 58°
m∠S = 2x + 7 = (2 x 58) + 7 = 123°
m∠T = x = 58°