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4 years ago

100 POINTS!!! PLEASE HELP ASAP!!!!

Mathematics

1 answer:

Makovka662 [10]4 years ago

6 0

Answer:

$\displaystyle \frac{1}{5} \\ \frac{211}{1500} \\ \frac{11}{300}$

Step-by-step explanation:

$\displaystyle \frac{1,8}{9} = 0,2 = \frac{1}{5}$

Greatest Common Divisor [GCD]: 9

$\displaystyle \frac{2,11}{15} = \frac{211}{1500}$

Greatest Common Divisor [GCD]: 1⁄100

$\displaystyle \frac{3,3}{90} = \frac{11}{300}$

Greatest Common Divisor [GCD]: 3⁄10

I am joyous to assist you.

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A pair of dice are tossed twice.Find the probability that both rolls give at most a sum of 8.

noname [10]

the probability that in bot rolls we have a sum of, at most, 8, is:

P = 47/ 1,296 = 0.036

<h3>How to find the probability?</h3>

The pair is tossed twice. A pair of dice has 36 possible outcomes, so if we toss twice the pair, the total number of outcomes is:

36*36 = 1,296

Now if we define the outcomes as:

{dice 1 (roll1), dice2(roll1), dice 1 (roll2), dice2(roll2) }

The outcomes that give at most a sum of 8 are:

{1, 1, 1, 1}

{2, 1, 1, 1} ( 3 permutations)

{2, 2, 1, 1} ( 6 permutations).

{2, 2, 2, 1} ( 3 permutations)

{3, 1, 1, 1} ( 3 permutations)

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{4, 1, 1, 1} (3 permutations)

{4, 2, 1, 1} (6 permutations)

{5, 1, 1 , 1} (3 permutations)

{2, 2, 2, 2}

These are all the outcomes that give a sum of, at most, 8.

If we add all the outcomes we get 47 outcomes.

Then the probability that in bot rolls we have a sum of, at most, 8, is:

P = 47/ 1,296 = 0.036

If you want to learn more about probability:

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