All categories

3 years ago

100 POINTS!!! PLEASE HELP ASAP!!!!

Mathematics

1 answer:

Makovka662 [10]3 years ago

6 0

Answer:

$\displaystyle \frac{1}{5} \\ \frac{211}{1500} \\ \frac{11}{300}$

Step-by-step explanation:

$\displaystyle \frac{1,8}{9} = 0,2 = \frac{1}{5}$

Greatest Common Divisor [GCD]: 9

$\displaystyle \frac{2,11}{15} = \frac{211}{1500}$

Greatest Common Divisor [GCD]: 1⁄100

$\displaystyle \frac{3,3}{90} = \frac{11}{300}$

Greatest Common Divisor [GCD]: 3⁄10

I am joyous to assist you.

You might be interested in

Will give brainliest ! 15 points please help <3

andrey2020 [161]

Answer:

1. C

2. G, H

3. A, H

4. x=-4.5

5. B, D, F, G

Step-by-step explanation:

pls Mark Brainliest

8 0

3 years ago

15 POINTS!!!!!!HELP ME PLS!

weqwewe [10]

Answer:

the answer is B

Step-by-step explanation:

6 0

3 years ago

State when the following equations and inequalities will be true and when they will be false.

-BARSIC- [3]

' 36 = 9k ' is not an inequality. It's an <u>equality</u>, usually called an <em><u>equation</u></em>.

It's true whenever 'k' is 4, and false at any other time.

(You can determine that simply by dividing each side of the equation by 9.)

6 0

3 years ago

The first step to solve the equation StartFraction x over 4 EndFraction minus three-fourths = 16 is shown below.

irina1246 [14]

Ok so the first step to solve it is subtraction then it’s multiplication then additions

4 0

3 years ago

Help please you don’t know how much this means to me

ICE Princess25 [194]

<h2>Problem 6:</h2><h2>a)</h2>

$a(0) = 1 \: \: \: \: \: \: b(0) = 2 \: \: \: \: \: c(0) = 3 \\ a(1) = b(0) + c(0) = 2 + 3 = 5 \\ b(1) = a(0) + c(0) = 1 + 3 = 4 \\ c(1) = a(0) + b(0) = 1 + 2 = 3 \\ \\ a(2) = b(1) + c(1) = 4 + 3 = 7 \\ b(2) = a(1) + c(1) = 5 + 3 = 8 \\ c(2) = a(1) + b(1) = 5 + 4 = 9$

$a(3) = b(2) + c(2) = 8 + 9 = 17\\ b(3) = a(2) + c(2) =7 + 9 = 16 \\ c(3) = a(2) + b(2) = 7 + 8 = 15 \\ \\ a(4) = b(3) + c(3) = 16 + 15 = 31 \\ b(4) = a(3) + c(3) = 17 + 15 = 32 \\ c(4) = a(3) + b(3) = 17 + 16 = 33$

$a(5) = 32 + 33 = 65 \\ b(5) = 31 + 33 = 64 \\ c(5) =31 + 32 = 63 \\ \\ a(6) = 64 + 63 = 127 \\ b(6) = 65 + 63 = 128 \\ c(6) = 65 + 64 = 129 \\$

$a(7) = 128 + 129 = 257 \\ b(7) = 127 + 129 = 256 \\c (7) = 127 + 128 = 255 \\ \\ a(8) = 256 + 255 = 511 \\ b(8) = 257 + 255 = 512 \\ c(8) = 257 + 256 = 513$

$a(9) = 512 + 513 = 1025 \\ b(9) = 511 + 513 = 1024 \\ c(9) = 511 + 512 = 1023 \\ \\ a(10) = 1024 + 1023 = 2047 \\ b(10) = 1025 + 1023 = 2048 \\ c(10) = 1025 + 1024 = 2049$

$a(n) + b(n) + c(n) = \\ 2(a(n - 1) + b(n - 1) + c(n - 1)) \\ 6 \times 2 {}^{n }$

$6 \times 2 {}^{n} > 100 \: 000 \\ 2 {}^{n} > \frac{100 \: 000}{6} \\ n > log {}^{2} ( \frac{100 \: 000}{6} ) \\ n > 14.02468 \\ n = 15$

<h2 />

5 0

2 years ago